Position <em>' C '</em> is the middle of the swing. That's where the weight is the lowest.
It's also the place where the weight is moving the fastest, so that means it's the place where the kinetic energy is greatest.
Answer:
Magnitude is 25.8 m/s and direction is 
Explanation:
From the law of conservation of linear momentum
where 
and 
are masses of bullet and stones respectively, 
and 
are the initial velocities of bullet and stone respectively, 
and 
are the final velocities of bullet and stone respectively
Substituting 6g=0.006 Kg for mass of bullet, 0.1Kg for mass of stone, 350 m/s for initial velocity of bullet and 250 m/s as final velocity for stone but initial velocity of stone is zero
Substituting 21 for 
and 15 for 
To find direction
Therefore, magnitude is 25.8 m/s and direction is
Answer:
Explanation:
F = 2.12 x 10⁻²⁶ / x²
Work done by electric field of nucleus
W = ∫ Fdx
= ∫2.12 x 10⁻²⁶ / x² dx
= 2.12 x 10⁻²⁶ ( - 1 / x )
= - 2.12 x 10⁻²⁶ ( 1/5 - 1 / 8 x 10⁻¹⁰ )
= - .265 x 10⁻¹⁶ J
1/ 2 x mv² = .5 x 1.67 x 10⁻²⁷ x 9 x 10¹⁰ - .265 x 10⁻¹⁶
= 7.515 x 10⁻¹⁷ - .265 x 10⁻¹⁶
=( .7515 - .265 )x 10⁻¹⁶
= .4865 x 10⁻¹⁶
.5 x 1.67 x 10⁻²⁷ x v² = .4865 x 10⁻¹⁶
v² = .5826 x 10¹¹
v² = 5.826 x 10¹⁰
v = 2.41 x 10⁵ m /s
b )
Let r be the closest distance
Potential at this point
2.12 x 10⁻²⁶ ( 1 / r )
Kinetic energy
= 0
Total energy = 2.12 x 10⁻²⁶ ( 1 / r )
Total energy at 5 m
= .5 x 1.67 x 10⁻²⁷ x 9 x 10¹⁰ + 0 ( potential energy at 5 m will be negligible as compared with that near the center )
= 7.515 x 10⁻¹⁷ J
So ,
2.12 x 10⁻²⁶ ( 1 / r ) = 7.515 x 10⁻¹⁷
r = 2.12 x 10⁻²⁶ / 7.515 x 10⁻¹⁷
= .282 x 10⁻⁹
= 2.82 x 10⁻¹⁰ m
c ) As electric field is conservative , no dissipation of energy takes place . Hence its speed at 5m on returning back to this point will be same as
3.00 x 10⁵ m /s
Answer:
105000km
Explanation:
Given parameters:
Speed of shuttle = 21000km/hr
Time of travel = 5hrs
Unknown:
The distance covered by the space shuttle;
Solution:
Distance is the length of the path traveled.
Distance = speed x time
Input the parameters and solve;
Distance = 21000km/hr x 5hrs
Distance = 105000km
B strength training I think that’s the answer
