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3 years ago

Two long parallel wires are placed side-by-side on a horizontal table. if the wires carry current in opposite directions,

Physics

1 answer:

STatiana [176]3 years ago

3 0

$\vec F = I (\vec L \times \vec B)$

if currents go in opposite directions, wires repel

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You're using a wedge to split a log. you are hitting the wedge with a large hammer to drive it into the log. it takes a force of

KIM [24]

The work performed on an object is the force multiplied by the distance it is moved, provided the movement is parallel to the force. Since that is the case here, we can get the work by W=Fd=1900N x 0.23m = 437J. This energy is used to split the wood.

6 0

3 years ago

Read 2 more answers

A 35 kg child goes down a playground that is inclined at an angle of 27.5 degrees above the horizontal. Find the acceleration if

tigry1 [53]

Answer:

4.16m/s²

Explanation:

According to Newtons second law;

$\sum Fx = ma_x\\Fm - Ff = ma_x\\W sin\theta - \mu R cos \theta = ma_x\\mg sin\theta - \mu mg cos\theta = ma_x\\$

Fm is the moving force

$\mu$ is the coefficient of kinetic friction between the child and the slide

m is the mass

g is the acceleration due to gravity

a is the acceleration of the child

Substitute the given values and get the acceleration as shown;

35(9.8)sin27.5 - 0.415(35)(cos27.5) = 35a

158.38-12.88 = 35a

145.49 = 35a

a = 145.49/35

a = 4.16m/s²

Hence the acceleration of the body is 4.16m/s²

4 0

3 years ago

A baby elephant trots in a straight line along a river. The horizontal position of the elephant in meters over

mote1985 [20]

Answer:

Displacement -6

Distance 24

Explanation:

5 0

3 years ago

A 2.0 m conductor is formed into a square and placed in the horizontal xy-plane. A magnetic field is oriented 30.0° above the ho

Gnesinka [82]

Answer:

$\phi_B = 0.216 T m^2$

Explanation:

As we know that the length of the conductor is given as

$L = 2 m$

now if it is converted into a square then we have

$L = 4a$

$a = \frac{L}{4} = 0.5 m$

now the are of the loop will be

$A = a^2 = 0.5(0.5) = 0.25 m^2$

now the magnetic flux is defined as

$\phi_B = BAcos\theta$

here we know

B = 1.0 T

$\theta = 30.0^o$

$\phi_B = (1.0 T)(0.25 m^2)(cos30)$

$\phi_B = 0.216 T m^2$

5 0

3 years ago

What average force is needed to accelerate a 9.20-gram pellet from rest to 125 m/s over a distance of 0.800 m along the barrel o

aleksklad [387]

Given:
u = 0, initial velocity
v = 125 m/s, final velocity
s = 0.0800 m, distance traveled
9.20 g, the mass of the pellet

If the acceleration is a, then
0² + 2*(a m/s²)*(0.800 m) = (125 m/s)²
1.6a = 15625
a = 9765.625 m/s²

Calculate the force.
F = (9.20 x 10⁻³ kg)*(9765.625 m/s²) = 98.84 N

Answer: 98.8 N (nearest tenth)

8 0

3 years ago