We can use the textbook results for head-on elastic collisions to analyze the recoil of the Earth when a ball bounces off a wall
embedded in the Earth. Suppose a professional baseball pitcher hurls a baseball (m = 155 grams = 0.155 kg) with a speed of 103 miles per hour (vball = 45.3 m/s) at a wall, and the ball bounces back with little loss of kinetic energy.(a) What is the recoil speed of the Earth (M = 6multiply1024 kg)?
2 answers:
Answer:
The explaination and attachment better portrays the answer. kindly check explaination.
Explanation:
To be able to solve for the kinetic energy and the recoil speed. Let have an understanding of those words.
Kinetic energy is the energy of motion. If an object is moving, it is said to have kinetic energy.
Please kindly check attachment for the detailed answer.
You might be interested in
Answer:
(a) θ = 33.86°
(b) Ay = 49.92 N
Explanation:
You have that the magnitude of a vector is A = 89.6 N
The x component of such a vector is Ax = 74.4 N
(a) To find the angle between the vector and the x axis you use the following formula for the calculation of the x component of a vector:
(1)
Ax: x component of vector A
A: magnitude of vector A
θ: angle between vector A and the x axis
You solve the equation (1) for θ, by using the inverse of cosine function:
the angle between the A vector and the x axis is 33.86°
(b) The y component of the vector is given by:
the y comonent of the vecor is Ay = 49.92 N