Explanation:
The acceleration of the object equals the gravitational acceleration. The mass, size, and shape of the object are not a factor in describing the motion of the object. So all objects, regardless of size or shape or weight, free fall with the same acceleration hope that helps
Answer:
Explanation:
Force of friction at car B ( break was applied by car B ) =μ mg = .65 x 2100 X 9.8 = 13377 N .
work done by friction = 13377 x 7.30 = 97652.1 J
If v be the common velocity of both the cars after collision
kinetic energy of both the cars = 1/2 ( 2100 + 1500 ) x v²
= 1800 v²
so , applying work - energy theory ,
1800 v² = 97652.1
v² = 54.25
v = 7.365 m /s
This is the common velocity of both the cars .
To know the speed of car A , we shall apply law of conservation of momentum .Let the speed of car A before collision be v₁ .
So , momentum before collision = momentum after collision of both the cars
1500 x v₁ = ( 1500 + 2100 ) x 7.365
v₁ = 17.676 m /s
= 63.63 mph .
( b )
yes Car A was crossing speed limit by a difference of
63.63 - 35 = 28.63 mph.
Answer:
Yes.
Voltage = resistance×current
Explanation:
There is a proportional relationship between voltage and current. Voltage varies directly as the current provided resistance is constant
Mathematically, voltage = resistance×current where resistance is constant
Answer:
206.62313 m/s
Explanation:
u = Muzzle speed
g = Acceleration due to gravity = 9.8 m/s²
= Angle at which the bullet is fired = 30°
h = Maximum height = 544 m
Maximum height is given by

The muzzle speed is 206.62313 m/s
The temperature of the air in the open orang pipe has been altered by 18.73° C
The frequency of an open orang pipe is estimated by using the formula:

Then, the combination of the frequency of the tuning fork and the open orang pipe is:

These combinations of frequency produce 4 beats per sound.
i.e.



When it is altered, the beats first diminish and increase again by 4.
i.e.


If we equate both equations (1) and (2) together, we have:

However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.
Hence;
- when the temperature of the pipe = unknown ???
- the temperature of the open orang pipe = 15
∴

By squaring both sides, we have:




T = 306.726912 - 273
T ≅ 33.73 ° C
∴
The change in temperature ΔT = 33.73° C - 15° C
The change in temperature ΔT = 18.73° C
Learn more about wave frequency here:
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