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lesya692 [45]
3 years ago
14

What effect does gravity have on a person living on earth?

Physics
1 answer:
GREYUIT [131]3 years ago
5 0
Pulling a person down so we stick to the surface
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How are mass and free fall related to acceleration?
Dmitrij [34]

Explanation:

The acceleration of the object equals the gravitational acceleration. The mass, size, and shape of the object are not a factor in describing the motion of the object. So all objects, regardless of size or shape or weight, free fall with the same acceleration hope that helps

4 0
3 years ago
Read 2 more answers
You are called as an expert witness to analyze the following auto accident: Car B, of mass 2100 kg, was stopped at a red light w
Artemon [7]

Answer:

Explanation:

Force of friction at car B ( break was applied by car B ) =μ mg = .65 x  2100 X 9.8  = 13377 N .

work done by friction = 13377 x 7.30 = 97652.1 J

If v be the common velocity of both the cars after collision

kinetic energy of both the cars = 1/2 ( 2100 + 1500 ) x v²

= 1800 v²

so , applying work - energy theory ,

1800 v² = 97652.1

v² = 54.25

v = 7.365 m /s

This is the common velocity of both the cars .

To know the speed of car A , we shall apply law of conservation of momentum  .Let the speed of car A before collision be v₁ .

So , momentum before collision = momentum after collision of both the cars

1500 x v₁ = ( 1500 + 2100 ) x 7.365

v₁ = 17.676 m /s

= 63.63 mph .

( b )

yes Car A was crossing speed limit by a difference of

63.63 - 35 = 28.63 mph.

7 0
3 years ago
2. Is there a proportional relationship between voltage and current? If so, write the equation for each run in the form potentia
stepan [7]

Answer:

Yes.

Voltage = resistance×current

Explanation:

There is a proportional relationship between voltage and current. Voltage varies directly as the current provided resistance is constant

Mathematically, voltage = resistance×current where resistance is constant

8 0
3 years ago
A gun is fired with angle of elevation 30°. What is the muzzle speed if the maximum height of the shell is 544 m? (Round your an
Artemon [7]

Answer:

206.62313 m/s

Explanation:

u = Muzzle speed

g = Acceleration due to gravity = 9.8 m/s²

\theta = Angle at which the bullet is fired = 30°

h = Maximum height = 544 m

Maximum height is given by

h=\dfrac{u^2sin^2\theta}{2g}\\\Rightarrow u=\sqrt{\dfrac{2gh}{sin^2\theta}}\\\Rightarrow u=\sqrt{\dfrac{2\times 9.81\times 544}{sin^2(30)}}\\\Rightarrow u=206.62313\ m/s

The muzzle speed is 206.62313 m/s

6 0
4 years ago
A tuning fork of frequency 254 Hz and an open orang pipe of slightly lower frequency are at 15oC. When
katovenus [111]

The temperature of the air in the open orang pipe has been altered by 18.73° C

The frequency of an open orang pipe is estimated by using the formula:

\mathbf{f = \dfrac{v}{2L}}

Then, the combination of the frequency of the tuning fork and the open orang pipe is:

\mathbf{254 - \dfrac{v}{2L} }

These combinations of frequency produce 4 beats per sound.

i.e.

\mathbf{254 - \dfrac{v}{2L}   =4}

\mathbf{ \dfrac{v}{2L} = 254-4 }

\mathbf{ \dfrac{v}{2L} = 250 ----(1)}

When it is altered, the beats first diminish and increase again by 4.

i.e.

\mathbf{ \dfrac{v'}{2L} = 254+4 }

\mathbf{ \dfrac{v'}{2L} = 258 --- (2) }

If we equate both equations (1) and (2) together, we have:

\mathbf{\dfrac{v'}{v}= \dfrac{258}{250}}

However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.

Hence;

  • when the temperature of the pipe  = unknown ???
  • the temperature of the open orang pipe = 15

∴

\implies \mathbf{\sqrt{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \dfrac{258}{250}}

By squaring both sides, we have:

\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \Big (\dfrac{258}{250}\Big )^2}

\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)= \Big (\dfrac{66564}{62500}\Big )}

\implies \mathbf{\Big(\dfrac{273 + T}{288}\Big)= \Big (1.065024\Big )}

\implies \mathbf{273 +T =306.726912  }

T = 306.726912 - 273

T ≅ 33.73 ° C

∴

The change in temperature ΔT = 33.73° C - 15° C

The change in temperature ΔT = 18.73° C

Learn more about wave frequency here:

brainly.com/question/14316711?referrer=searchResults

4 0
3 years ago
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