All categories

3 years ago

What effect does gravity have on a person living on earth?

Physics

1 answer:

GREYUIT [131]3 years ago

5 0

Pulling a person down so we stick to the surface

You might be interested in

Agatha has 1kg samples of two substance- A and B. Substance A has a higher specific heat capacity than substance B. Both samples

Sav [38]

Answer:

Substance A will release more heat.

Explanation:

Let suppose that both substances experiment an entirely sensible heat process and are incompressible and begin at the same temperature. Physically speaking, specific heat ( $c$ ), measured in kilojoules per kilogram-degree Celsius, can be described by following expression:

$c = \frac{Q}{m\cdot (T_{f}-T_{o})}$ (1)

Where:

$Q$ - Released heat, measured in kilojoules.

$m$ - Sample mass, measured in kilograms.

$T_{o}$ , $T_{f}$ - Initial and final temperatures of the sample, measured in degrees Celsius.

If we know that $c_{A}> c_{B}$ , $m_{A} = m_{B}$ , $T_{A,o} = T_{B,o}$ and $T_{A,f} = T_{B,f}$ , then we have the following inequation:

$\frac{Q_{A}}{m\cdot (T_{A,f}-T_{A,o})} > \frac{Q_{B}}{m\cdot (T_{B,f}-T_{B,o})}$

$Q_{A} > Q_{B}$

Substance A will release more heat.

7 0

3 years ago

Why is pH so important to maintain life?

morpeh [17]

I think they are right! When one of the answers is, all of the above, that is usually the correct answer. pH is important to all living things.

4 0

3 years ago

A small charged sphere is attached to a thread and placed in an electric field. The other end of the thread is anchored so that

VMariaS [17]

Answer:

$E = 9.66\times 10^{-6} N/C$

direction is Horizontal

Explanation:

As we know that the string is horizontal here

so the tension force in the string is due to electrostatic force on it

now we will have

$F = qE$

so here the force is tension force on it

$F = 6.57 \times 10^{-2} N$

$Q = 6.80 \times 10^3 C$

now we have

$6.57 \times 10^{-2} = (6.80 \times 10^3)E$

$E = 9.66\times 10^{-6} N/C$

direction is Horizontal

4 0

4 years ago

A spring with a mass of 1 kg has a spring constant 43 kg/s2. If the spring begins at equilibrium position and is given a velocit

Alexxandr [17]

Answer:

Damping constant is equal to $2\sqrt{43}$

Explanation:

We have given mass m = 1 kg

Spring constant is given $k=43kg/sec^2$

For critical damping $\zeta =1$

We have to find the damping constant

Damping constant is equal to $\zeta =\frac{c}{2\sqrt{\frac{k}{m}}}$

So $1 =\frac{c}{2\sqrt{\frac{k}{m}}}$

$c=2\sqrt{\frac{k}{m}}$

$=2\sqrt{\frac{43}{1}}=2\sqrt{43}$

So damping constant is equal to $2\sqrt{43}$

5 0

4 years ago

A charged comb often attracts small bits of dry paper that then fly away when they touch the comb. Explain why that occurs.

MAVERICK [17]

Explanation:

Since the comb has a net charge, it attracts the paper, which has a net charge equal to zero. When the paper touches the comb, an electrical interaction is established between the charge of the comb and the neutral paper, because of this, the paper now has a net charge with the same sign of the comb and they repel.

7 0

3 years ago