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3 years ago

How does you body reproduce

Physics

1 answer:

Ivahew [28]3 years ago

6 0

I didn’t know exactly how to explain it so I googled it and this is what I got

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If the magnitude of F1 is greater than the magnitude of F2, then the box is

Lady bird [3.3K]

Assuming that the vectors are acting along the same axis, we could just simply add or subtract the vectors. Since the F1 is greater than F2, there would be motion, there would be acceleration, and that the direction of motion is along the F1.

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3 years ago

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Yosef applies an input force of 50 N to a crowbar. The crowbar applies a force of 750 N to the lid of a crate. What is the mecha

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The mechanical advantage of the crowbar is 15.

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3 years ago

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A guitar string is 0.620m long, and oscillates at 234Hz. What is the velocity of the waves in the string? m/s

9966 [12]

Answer:

v = 72.54 m/s

Explanation:

We have,

Length of a guitar string is 0.62 m

Frequency of a guitar string is 234 Hz

For guitar string,

$L=2\lambda\\\\\lambda=\dfrac{L}{2}\\\\\lambda=\dfrac{0.62}{2}\\\\\lambda=0.31\ m$

The velocity of the wave in the string is given by :

$v=f\lambda\\\\v=234\times 0.31\\\\v=72.54\ m/s$

So, the velocity of the waves in the string is 72.54 m/s.

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3 years ago

If a car is moving backward and has negative acceleration, what can be said about the speed of the car?

KATRIN_1 [288]

I think its A let me know its wrong or not

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3 years ago

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A mass free to vibrate on a level, frictionless surface at the end of a horizontal spring is pulled 35 cm from its equilibrium p

saul85 [17]

Answer:

0.67 s

Explanation:

This is a simple harmonic motion (SHM).

The displacement, $x$ , of an SHM is given by

$x = A\cos(\omega t)$

A is the amplitude and $\omega$ is the angular frequency.

We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or $\frac{\pi}{4}$ radian.