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USPshnik [31]
3 years ago
5

the figure below represents a wooden block whose dimensions are 2m by 0.2m by 0.2m.calculate the volume of the block and the mas

s of the block if it's density is 600kg/m3​
Physics
1 answer:
Law Incorporation [45]3 years ago
5 0

Answer:

0.08 m^3, 48 kg

Explanation:

The density of an object is the amount of mass contained per unit of volume.

Density is given by the equation

d=\frac{m}{V}

where

m is the mass of the object

V is its volume

In this problem, we have a wooden block of dimensions:

2 m, 0.2 m, 0.2 m

So, the volume of the block is

V=(2)(0.2)(0.2)=0.08 m^3

We also know that the density of the block is

d=600 kg/m^3

Therefore, the mass of the block is

m=dV=(600)(0.08)=48 kg

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You attach a 1.70 kg block to a horizontal spring that is fixed at one end. You pull the block until the spring is stretched by
Usimov [2.4K]

Answer:

maximum speed of the block is 3.14 m/s

Explanation:

given data

mass = 1.70 kg

stretch in the spring = 0.2 m

time take by block to come to zero  t = 0.2 s

solution

we know that Time period of oscillation (T) that is express as

T = 2t    ......................1

put here value

T = 2 (0.2)

T = 0.4 s

so here time period is express as

T = 2\pi \sqrt{\frac{m}{k}}     ................2

here k is spring constant of the spring so  put here value

0.4  =  2(\pi ) \sqrt{\frac{1.70}{k}}  

here k will be

k = 419.02 N/m

so we use here conservation of energy that is

Maximum kinetic energy = Maximum spring potential energy   ............3

(0.5) m v² = (0.5) k x²

here v is maximum speed block

so put here value and we get

(1.70) v² = (419.02) (0.2)²

v = 3.14 m/s

so maximum speed of the block is 3.14 m/s

8 0
3 years ago
Rachel has been reading her physics book. She takes her weighing scales into an elevator and stands on them. If her normal weigh
GrogVix [38]

Answer:

345 N

Explanation:

Given:

Normal weight of Rachel (mg) = 690 N

Case 1: Upward motion of elevator

Given:

Acceleration of elevator (a) = 0.25 g

The scale reading is given by the normal force acting on Rachel. Let N₁ be the normal force.

So, the net force acting on Rachel is given as:

F_{net}=N_1-mg=N_1-690

Now, from Newton's second law:

F_{net}=ma\\\\N_1-690=m\times 0.25g\\\\N_1-690=0.25\times (mg)\\\\N_1-690=0.25\times 690\\\\N_1=690+172.5=862.5\ N------(1)

Case 2: Downward motion of elevator

Given:

Acceleration of elevator (a) = 0.25 g

The scale reading is given by the normal force acting on Rachel. Let N₂ be the normal force.

So, the net force acting on Rachel is given as:

F_{net}=mg-N_2=690-N_2

Now, from Newton's second law:

F_{net}=ma\\\\690-N_2=m\times 0.25g\\\\690-N_2=0.25\times (mg)\\\\690-N_2=0.25\times 690\\\\N_2=690-172.5=517.5\ N------(2)

Now, the difference in the scale reading is obtained by subtracting equation (2) from equation (1). This gives,

Difference=N_1-N_2=862.5-517.5=345\ N

Therefore, the difference between the up and down scale readings is 345 N.

4 0
3 years ago
A net force of 100 N is moving a mass with an acceleration of 5 m/s2. What is the mass of the object?
olya-2409 [2.1K]
Fnet=ma so m = fnet/a   100/5=20 the mass is 20
7 0
3 years ago
The apparent reversal of motion of planets against the backdrop of fixed stars is called
Free_Kalibri [48]

The planets move eastward against the background of fixed stars with the exception of Venus, Uranus and Pluto moving westward as seen in Earth's sky . This apparent retreating movement is called Retrograde motion. It is illusion created by Earth's movement going by outer planets in their respective orbits.

7 0
3 years ago
Read 2 more answers
Which particles do not affect the stability of the atom
lutik1710 [3]
Electrons


20charachters
5 0
3 years ago
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