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USPshnik [31]
2 years ago
5

the figure below represents a wooden block whose dimensions are 2m by 0.2m by 0.2m.calculate the volume of the block and the mas

s of the block if it's density is 600kg/m3​
Physics
1 answer:
Law Incorporation [45]2 years ago
5 0

Answer:

0.08 m^3, 48 kg

Explanation:

The density of an object is the amount of mass contained per unit of volume.

Density is given by the equation

d=\frac{m}{V}

where

m is the mass of the object

V is its volume

In this problem, we have a wooden block of dimensions:

2 m, 0.2 m, 0.2 m

So, the volume of the block is

V=(2)(0.2)(0.2)=0.08 m^3

We also know that the density of the block is

d=600 kg/m^3

Therefore, the mass of the block is

m=dV=(600)(0.08)=48 kg

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"a horn emits a frequency of 1000 HZ. A 14 m/s wind is blowing toward a listener. What is the frequency of the sound heard by th
Semenov [28]

Answer:

 f_L = 1000 Hz

Explanation:

given,

speed of wind, = 14 m/s

frequency of horn,f_s = 1000 Hz

speed of sound,V = 344 m/s

frequency heard by the listener

using Doppler effect

f_L = \dfrac{v+v_L}{v+v_s}f_s

f_L is the frequency of the sound heard by the listener

f_s is the frequency of sound emitted by the listener

V is the speed of sound

v_L is the speed of listener

v_s is the speed of source

now,

considering the frame of reference in which wind is at rest now, both listener and the source will be moving at 14 m/s

 f_L = \dfrac{v+14}{v+14}\times 1000

now on solving we will get

 f_L = 1000 Hz

hence, the frequency heard by the listener is equal to  1000 Hz

 

7 0
3 years ago
It takes 399 newtons to move a 7.2 kg object. What is the acceleration of the object?
Nookie1986 [14]

Answer:

a = 55.42m/s²

Explanation:

F = m*a

F = force(Newtons)

m = mass

a = acceleration

a = F/m

a = 399N/7.2kg

a = 55.42m/s²

8 0
2 years ago
Two physics students, Ben and Bonnie, are in the weightlifting room. Bonnie lifts the 50 kg barbell over her head (approximately
KatRina [158]

Answer:

Both of them

Explanation:

5 0
2 years ago
Two particles with oppositely signed charges nC are placed at two of the vertices of an equilateral triangle with side length 3
babymother [125]

The magnitude of the electric field at the third vertex of the triangle is determined as zero.

<h3>Electric field at the third vertex of the triangle </h3>

The electric field at the third vertex of the equilateral triangle due to the other charges placed on the first and second vertices is calculated as follows;

E = E(13) + E(23)

E = (kq₁)/r² + (kq₂)/r²

where;

  • q1 is positive charge
  • q2 is negative charge

E =  (kq₁)/r² - (kq₂)/r²

E = 0

Thus, the magnitude of the electric field at the third vertex of the triangle is determined as zero.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

5 0
1 year ago
An object of mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons. Calcuate the acceleration
rjkz [21]

Answer:

this answer you question

6 0
2 years ago
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