the figure below represents a wooden block whose dimensions are 2m by 0.2m by 0.2m.calculate the volume of the block and the mas
1 answer:
Answer:
, 48 kg
Explanation:
The density of an object is the amount of mass contained per unit of volume.
Density is given by the equation
where
m is the mass of the object
V is its volume
In this problem, we have a wooden block of dimensions:
2 m, 0.2 m, 0.2 m
So, the volume of the block is
We also know that the density of the block is
Therefore, the mass of the block is
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The question can be solved using conservation of linear momentum.
= 0.06kg and
= 0.03kg
Let the initial velocity of Marble A be , = 0.7m/s
Let the initial velocity of Marble B be, = 0m/s
Let the velocity of Marble A after collisiong , = -0,02m/s
Let the velocity of Marble B after collision be
From the conservation of linear momentum equation. We get,
Substituting the values we get,
(0.06)(0.7) + 0 = (0.06)(-0.02) + (0.03)
we get, = 1.44m/s
Answer:
V₂ = 1.5 m/s
Explanation:
given,
speed of the first piece = 6 m/s
speed of the third piece = 3 m/s
speed of the second fragment = ?
mass ratios = 1 : 4 : 2
fragment break fly off = 120°
α = β = γ = 120°
sin α = sin β = sin γ = 0.866
using lammi's theorem
A,B and C is momentum of the fragments
4 x V₂ = 2 x 3
V₂ = 1.5 m/s
