The eccentricity of the conic section that is graphed is C. One.
<h3>What is eccentricity?</h3>
It should be noted that the eccentricity of the clinic section simply means the distance from the point to its focus.
In this case, the eccentricity of the conic section that is graphed is one. The eccentricity value is usually constant for any conics.
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9514 1404 393
Answer:
(d) reflection about the x-axis, up 6 units
Step-by-step explanation:
The parent function y=1/x is multiplied by -1, which reflects it over the x-axis. Then 6 is added, which shifts it up 6 units.
The transformations are ...
reflection about the x-axis, up 6 units
The most appropriate choice for similarity of triangles will be given by -
Speed of tip of the shadow of woman = 6 ft/s
What are similar triangles?
Two triangles are said to be similar, if the corrosponding angles of the triangles are same and the corrosponding sides of the triangles are in the same ratio.
Here,
The diagram has been attached here
Let the distance of woman from the pole be x ft and the distance of tip of the shadow to the pole be y ft.
Height of street light = 18 ft
Height of woman = 6ft
The two triangles are similar [As height of woman is parallel to the height of pole]

To find the speed, we have to differentiate both sides with respect to time 't'

Speed of tip of her shadow = 6 ft
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<h2>
Greetings!</h2>
Answer:
$25830
Step-by-step explanation:
If 100% of the car price is 24,600 , then you can imagine that extra 5% being added to this
100 + 5 = 105
So you need to find what 105% of the cost was.
To do this you can use the percentage formula:
Amount x 
Now, you can simply plug the values into this
24,600 x 
24600 x 1.05 = 25830
<h3>So the total cost including tax would be $25830!</h3><h3 /><h2>Hope this helps!</h2>
Answer:
The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).