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xeze [42]
3 years ago
12

The moon and other satellites rotate around the earth. Identify the force that keeps these satellites in orbit. A) gravity B) fr

iction C) a strong force D) electromagnetic force
Physics
2 answers:
TEA [102]3 years ago
5 0

Answer:

gravity

Explanation:

RoseWind [281]3 years ago
4 0
The force is gravity
You might be interested in
When a runner increases her speed from 75 m/s to 115 m/s in 25 s,her acceleration is _____
Angelina_Jolie [31]
The acceleration would actually be 1.6 m/s^2. Acceleration= final velocity-initial velocity/time taken. When you do that formula it comes out to equal that.
8 0
3 years ago
A racquet ball with mass m = 0.221 kg is moving toward the wall at v = 13.9 m/s and at an angle of θ = 25° with respect to the h
Salsk061 [2.6K]

Answer:

1) 3.07kgm/s

2) 5.56kgm/s

3) 76.16N

4) 4.33kgm/s

5) 0.57s

6) -8.66J

Explanation:

Given

m = 0.221kg

v = 13.9m/s

θ = 25°

t = 0.073s

1) to get the magnitude of the initial momentum is the racquet ball. We use the formula,

P(i) = mv(i)

P(i) = 0.221 * 13.9

P(i) = 3.07kgm/s

2) Magnitude of the change in momentum of the ball,

P(i,x) = P(i) cos θ

P(i,x) = 3.07 * cos25

P(i,x) = 3.07 * 0.9063

P(i,x) = 2.78

ΔP = 2P(i,x)

ΔP = 2 * 2.78 = 5.56kgm/s

3) magnitude of the average force exerted by the wall,

F(ave) = ΔP/Δt

F(ave) = 5.56/0.073

F(ave) = 76.16N

4) ΔP(z) = mv(f) - mv(i)

ΔP(z) = 0.221*-7.8 - 0.221*11.8

ΔP(z) = -1.72 - 2.61

ΔP(z) = 4.33kgm/s

5) F(ave) = ΔP/Δt

Δt = ΔP/F(ave)

Δt = 4.33 / 76.16

Δt = 0.57s

6) KE(i) = 0.5mv(i)²

KE(f) = 0.5mv(f)²

ΔKE = 0.5m[v(f)² - v(i)²]

ΔKE = 0.5 * 0.221 [(-7.8)² - 11.8²]

ΔKE = 0.1105 ( 60.84 - 139.24 )

ΔKE = 0.1105 * -78.4

ΔKE = -8.66J

6 0
3 years ago
A string fixed at both ends is 8.40 m long and has a mass of 0.120 kg. It is subjected to a tension of 96.0 N and set oscillatin
Luden [163]

Answer:

81.9756 m/s

16.8 m

4.8795 Hz

Explanation:

m = Mass of string = 0.12 kg

L = Length of string = 8.4 m

T = Tension on string = 96 N

Linear density is given by

\mu=\dfrac{m}{L}\\\Rightarrow \mu=\dfrac{0.12}{8.4}

Spee of the wave is given by

v=\sqrt{\dfrac{T}{\mu}}\\\Rightarrow v=\sqrt{\dfrac{96}{\dfrac{0.12}{8.4}}}\\\Rightarrow v=81.9756\ m/s

The speed of the waves on the string is 81.9756 m/s

Wavelength is given by

\lambda=2L\\\Rightarrow \lambda=2\times 8.4\\\Rightarrow \lambda=16.8\ m

The longest possible wavelength is 16.8 m

Frequency is given by

f=\dfrac{v}{\lambda}\\\Rightarrow f=\dfrac{81.9756}{16.8}\\\Rightarrow f=4.8795\ Hz

The frequency of the wave is 4.8795 Hz

3 0
3 years ago
Masses m and 2m approach each other at the same speed v and collide head-on. Find the final speed of mass 2m, if mass rebounds a
antoniya [11.8K]

Answer:

<em>The rebound speed of the mass 2m is v/2</em>

Explanation:

I will designate the two masses as body A and body B.

mass of body A = m

mass of body B = 2m

velocity of body A = v

velocity of body B = -v    since they both move in opposite direction

final speed of mass A = 2v

final speed of body B = ?

The equation of conservation of momentum for this system is

mv - 2mv = -2mv + x

where x is the final momentum of the mass B

x = mv - 2mv + 2mv

x = mv

to get the speed, we divide the momentum by the mass of mass B

x/2m = v = mv/2m

speed of mass B = <em>v/2</em>

6 0
3 years ago
Pls pls pls pls help!!!!!
Natasha2012 [34]

Answer:

The net upward force the man experiences is approximately 1,324.8 N

The net downward force the man experienced is approximately 556.8 N

Explanation:

The given mass of the man, m = 96 kg

The acceleration of the elevator, a = 4.0 m/s²

According to Newton's third law of motion which states that action ad reaction are equal and opposite, when the elevator moves upwards, we have;

The net force the man experiences, F = Gravitational force, m·g + The force of the elevator pushing upwards, m·a

∴ ↑F = m·g + m·a

Where;

F = The net force the man experiences

m = The mass of the man = 96 kg

g = The acceleration due to gravity ≈ 9.8 m/s²

a = The acceleration of the elevator = 4 m/s²

∴ ↑F = 96 kg × 9.8 m/s² + 96 kg × 4 m/s² ≈ 1,324.8 N

The net upward force the man experiences ≈ 1,324.8 N

When the elevator moves downwards, we have;

The net force the man experiences, F = Gravitational force, m·g + The loss of the gravitational force as the floor moves further downwards, -(m·a)

∴ F = m·g + -(m·a) = m·g - m·a

F = m·g - m·a

∴ ↓F = 96 kg × 9.8 m/s² - 96 k × 4 m/s² ≈ 556.8 N

The net downward force the man experienced ≈ 556.8 N

8 0
2 years ago
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