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xeze [42]
3 years ago
12

The moon and other satellites rotate around the earth. Identify the force that keeps these satellites in orbit. A) gravity B) fr

iction C) a strong force D) electromagnetic force
Physics
2 answers:
TEA [102]3 years ago
5 0

Answer:

gravity

Explanation:

RoseWind [281]3 years ago
4 0
The force is gravity
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What evidence supported the Oscillating Big Bang?
stira [4]
<h2>Answer with Explanation </h2>

The Oscillating Universe Theory is a cosmological model that consolidates both the Big Bang and the Big Crunch as a major aspect of a repeating occasion. That is, in the event that this hypothesis remains constant, the Universe in which we live in exists between a Big Bang and a Big Crunch.

As such, our universe can be the first of a conceivable arrangement of universes or it tends to be the nth universe in the arrangement.

As we probably are aware, in the Big Bang Theory, the Universe is accepted to extend from a hot, exceptionally thick, and little element. Actually, on the off chance that we extrapolate back to the snapshot of the Big Bang, we can achieve a point of peculiarity described by unendingly high vitality and thickness, just as zero volume.

This portrayal would just mean a certain something every one of the laws of material science will be tossed out of the window. This is naturally unsuitable to physicists. To exacerbate the situation, a few cosmologists even trust that the Universe will, in the end, achieve the greatest purpose of development and that once this occurs, it will at that point crumple into itself.

This will basically prompt indistinguishable conditions from when we extrapolate back to the snapshot of the Big Bang. To cure this difficulty, a few researchers are suggesting that maybe the Universe won't achieve the purpose of peculiarity all things considered.

5 0
3 years ago
Two objects of equal mass are a fixed distance apart. If the mass of each object could be tripled, the gravitational force betwe
antiseptic1488 [7]

gravitational force between two objects is given as

F = G m₁ m₂/r²

where m₁ = mass of first object , m₂ = mass of second object , r = distance between the two objects .

Initial case :

m₁ = m₂ = m

gravitational force between the objects is given as

F = G m²/r²

Final Case :

m₁ = m₂ = 3 m

new gravitational force between the objects is given as

F' = G (3m)²/r²

F' = 9 G m²/r²

F' = 9 F

hence the gravitational force between the two objects becomes 9 times.

5 0
3 years ago
Positive ions from a base and negative ions from an acid form a .
Trava [24]

Positive ions from a base and negative ion from an acid form salt.

 

<span>To add, table salt or common salt is a mineral composed primarily of sodium chloride, a chemical compound belonging to the larger class of salts. Rock salt or halite is also the common term for salt in its natural form.</span>

3 0
3 years ago
Read 2 more answers
A bar on a hinge starts from rest and rotates with an angular acceleration α = 12 + 5t, where α is in rad/s2 and t is in seconds
Rama09 [41]

Answer:

Ф = 239.73 rad

Explanation:

α = 12 + 15×t

W = ∫α×dt

   = ∫(12 + 5×t)×dt

   = 12×t + 2.5×t^2

then:

Ф = ∫W×dt

   = ∫(12×t + 2.5×t^2)dt

   = 6×t^2 + 5/6×t^3

therefore the angle at t = 4.88s is:

Ф = 6×(4.88)^2 + 5/6×(4.88)^3

   = 239.73 rad    

5 0
3 years ago
A parallel-plate capacitor with plates of area 360 cm2 is charged to a potential difference V and is then disconnected from the
Softa [21]

Answer:

Q=3.9825\times 10^{-9} C

Explanation:

We are given that a parallel- plate capacitor is charged to a potential difference V and then disconnected from the voltage source.

1 m =100 cm

Surface area =S=\frac{360}{10000}=0.036 m^2

\Delta d=0.8 cm=0.008 m

\Delta V=100 V

We have to find the charge Q on the positive plates of the capacitor.

V=Initial voltage between plates

d=Initial distance between plates

Initial Capacitance of capacitor

C=\frac{\epsilon_0 S}{d}

Capacitance of capacitor after moving plates

C_1=\frac{\epsilon_0 S}{(d+\Delta d)}

V=\frac{Q}{C}

Potential difference between plates after moving

V=\frac{Q}{C_1}

V+\Delta V=\frac{Q}{C_1}

\frac{Qd}{\epsilon_0S}+100=\frac{Q(d+\Delta d)}{\epsilon_0S}

\frac{Q(d+\Delta d)}{\epsilon_0 S}-\frac{Qd}{\epsilon_0S}=100

\frac{Q\Delta d}{\epsilon_0 S}=100

\epsilon_0=8.85\times 10^{-12}

Q=\frac{100\times 8.85\times 10^{-12}\times 0.036}{0.008}

Q=3.9825\times 10^{-9} C

Hence, the charge on positive plate of capacitor=Q=3.9825\times 10^{-9} C

6 0
3 years ago
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