Stark contrast to paths on energy surfaces or even mechanistic reactions, rule-based and inductive computational approaches to reaction prediction mostly consider only overall transformations. Overall transformations are general molecular graph rearrangements reflecting only the net change of several successive mechanistic reactions. For example, Figure 1 shows the overall transformation of an alkene interacting with hydrobromic acid to yield the alkyl bromide along with the two elementary reactions which compose the transformation.
At the point of maximum displacement (a), the elastic potential energy of the spring is maximum:

while the kinetic energy is zero, because at the maximum displacement the mass is stationary, so its velocity is zero:

And the total energy of the system is

Viceversa, when the mass reaches the equilibrium position, the elastic potential energy is zero because the displacement x is zero:

while the mass is moving at speed v, and therefore the kinetic energy is

And the total energy is

For the law of conservation of energy, the total energy must be conserved, therefore

. So we can write

that we can solve to find an expression for v:
Examples:
<span>Air </span>
<span>Blood </span>
<span>Mouthwash </span>
<span>Rubbing Alcohol </span>
<span>Peroxide </span>
<span>Hand-sanitizer </span>
<span>Perfume </span>
<span>Some bath gels </span>
<span>Coffee </span>
<span>Chicken or Beef Broth </span>
<span>Body Spray </span>
<span>Natural Oils </span>
<span>A heterogeneous mixture is a mixture where the components of the mixture are not uniform or have localized regions with different properties. </span>
<span>Examples: </span>
<span>Rocks </span>
<span>Oil and water </span>
<span>Soup </span>
<span>Pizza </span>
<span>Copper sulfate </span>
<span>Salsa </span>
<span>Chicken soup </span>
<span>Cottage cheese
hope that helped</span>
Answer:
(a) - 42700 m/s
(b) - 6.8 x 10^-4 m/s^2
Explanation:
initial velocity of star, u = 20.7 km/s
Final velocity of star, v = - 22 km/s
time, t = 1.99 years
Convert velocities into m/s and time into second
So, u = 20700 m / s
v = - 22000 m/s
t = 1.99 x 365.25 x 24 x 3600 = 62799624 second
(a) Change in planet's velocity = final velocity - initial velocity
= - 22000 - 20700 = - 42700 m/s
(b) Accelerate is defined as the rate of change of velocity.
Acceleration = change in velocity / time
= ( - 42700 ) / (62799624) = - 6.8 x 10^-4 m/s^2
Answer:
The last two bearings are
49.50° and 104.02°
Explanation:
Applying the Law of cosine (refer to the figure attached):
we have
x² = y² + z² - 2yz × cosX
here,
x, y and z represents the lengths of sides opposite to the angels X,Y and Z.
Thus we have,

or

substituting the values in the equation we get,

or

or
X = 26.47°
similarly,

or

or
Y = 49.50°
Consequently, the angel Z = 180° - 49.50 - 26.47 = 104.02°
The bearing of 2 last legs of race are angels Y and Z.