Answer:
cost of running the furnace during January is $5619.62
Explanation:
given data
runs a day = 13 hours
January days = 31 days
resistance = 7.2 ohm
current = 16.7 A
cost of electricity = $0.10/kWh
to find out
cost of running the furnace during January
solution
first we get her power consumed by furnace that is
Power consumed = 
........1
put here value we get
Power consumed = 
Power consumed = 38.7347 W
and
Power consumed by furnace in one hour is
Power consumed by furnace in one hour is = Power consumed × 3600
Power consumed by furnace in one hour is = 38.7347 × 3600
Power consumed by furnace in one hour is 139.445kWh
and
Power consumed by furnace in the month of January is
Power consumed by furnace in the month of January = 139.445kWh × 13 hours × 31 days
Power consumed by furnace in the month of January = 56196.335 kWh
so
cost of running the furnace during January is = $0.10/kWh × 56196.335 kWh
cost of running the furnace during January is $5619.62
Given parameters:
Mass on earth = 50kg
Unknown:
Mass on planet Xenon = ?
Weight on planet Xenon = ?
Mass is the amount of matter contained in a particular substance.
Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.
Weight = mass x acceleration due to gravity
Planet Xenon has half the gravitational force of Earth.
This translated gives 
= 4.9m/s²
Now, mass is always the same every where if the amount of matter in a substance does not change.
In this problem, mass = 50kg on planet xenon.
Weight = mass x acceleration due to gravity = 50 x 4.9 = 245N
The weight on Xenon is 245N and the mass is 50kg
About a mil sience 2014-2015
Not entirely sure if you're saying Homologous , but assuming you do , the homologous chromosomes seperate in the anaphase stage of Mitsosis of the Cell cycle
Answer:
A.The spring constant for B is one quarter of the spring constant for A.
Explanation:
If spring A oscillates at twice the frequency of spring B, and period is frequency inverted. It means spring B has a period twice of spring A's.
As 
, and the 2 springs have the same mass
So A.The spring constant for B is one quarter of the spring constant for A. is the correct answer.
