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The answer is: <em>Zero</em> work is done.
"Work", in the formal Physics usage, means a force acting through a distance. If you're holding a bag of apples UP but it's not moving UP, then your force is not moving through a distance, and the quantity of work is zero.
Answer:
The change in energy of the gas during the process is
joules.
Explanation:
We can represent this process by the First Law of Thermodynamics, in which gas does work on its surroundings and absorbs heat from there to describe its change in energy. In other words:
![Q_{in} - W_{out} = \Delta E](https://tex.z-dn.net/?f=Q_%7Bin%7D%20-%20W_%7Bout%7D%20%3D%20%5CDelta%20E)
Where:
- Heat absorbed by the gas, measured in joules.
- Work done by the gas, measured in joules.
- Change in energy, measured in joules.
If we know that
and
, the change in energy of the gas is:
![\Delta E = 1.36\times 10^{2}\,J-3.19\times 10^{2}\,J](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%201.36%5Ctimes%2010%5E%7B2%7D%5C%2CJ-3.19%5Ctimes%2010%5E%7B2%7D%5C%2CJ)
![\Delta E = -1.83\times 10^{2}\,J](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20-1.83%5Ctimes%2010%5E%7B2%7D%5C%2CJ)
The change in energy of the gas during the process is
joules.
Answer:
the answer will be 5.6 j..
hope you like the answer.....
Answer:
Explanation:
Givens
vi = 10 m/s
a = 1.5 m/s^2
d = 600 m
vf = ?
Formula
vf^2 = vi^2 + 2*a*d
Solution
vf^2 = 10^2 + 2*1.5 * 600
vf^2 = 100 + 1800
vf^2 = 1900
sqrt(vf^2) = sqrt(1900)
vf = 43.59 m/s