Answer:
Fields and variables are proportional
Explanation:
To solve the problem we must first identify the Vector Intensity,
The intensity is given by:

We also know that the change given by the Intensity is always the square of the amplitude,
This is,

The intensity is <em>proportional</em> to the change exerted on 
That is to say that in turn the amplitus is <em>proportional</em> to the Intensity.
On the other hand, relating the two variables we have


In this way we can conclude that the electric field of intensity is also <em>proportional</em> to 
Answer:
P = 200 W
Explanation:
The expression for the power is
P = W / t
the job
W = F d
we substitute
P = F d / t
P = F. v
We apply this equation to our case where the velocity is
v = (5 i + 3j + 6k) m / s
and the force is
F = (10i + 10j +20 k) N
we substitute in the power equation, remember that the scalar product of the unit vectors is
i.i = j.j = k.k = 1 and the other products are zero
P = 10 5 + 10 3 + 20 6
P = 200 W
Answer:

Explanation:
We are asked to calculate the force you are applying to a car. According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, we can use the following formula to calculate force.

The mass of the car is 2000 kilograms and the acceleration is 0.5 meters per second squared.
Substitute the values into the formula.

Multiply.

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 100 kilogram meters per second square is equal to 100 Newtons.

You apply <u>100 Newtons</u> of force to the car.
In short, those arms are made of "stars, dust and gas". They are visible as spiral arms because they have a higher density of those objects than the space between them.
The arms are an area where the density of stars (and planets and other objects) is unusually high and where the start are young - recently formed- and this also gives those starts their visibility as young starts are also very bright.
Explanation:
direction of electric field is same as that of force experienced by the test charge