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kykrilka [37]
2 years ago
14

Which of the following effects is produced by the high surface tension of water? Which of the following effects is produced by t

he high surface tension of water? A water strider can walk across the surface of a small pond. Water flows upward from the roots to the leaves in plants. Evaporation of sweat from the skin helps to keep people from overheating. Lakes don't freeze solid in winter despite low temperatures. Organisms resist temperature changes, although they give off heat due to chemical reactions.
Physics
1 answer:
Mashcka [7]2 years ago
7 0

<u>Answer:</u>

<em>A water strider can walk along the surface of earth due to the surface tension of water. </em>

<u>Explanation:</u>

Fluids have a <em>tendency to shrink to minimum possible surface area</em> and this is called surface tension. It usually occurs due to the greater force of cohesion between molecules of same substance when compared to adhesive force between molecules of different substances. Objects with greater densities can float along water surface due to the <em>role played by surface tension. </em>

When insects walk along the water surface they  are pulled down due to gravity. But  the  force of attraction  between the legs of the insect and water molecules is minimal. Thus the surface tension would always tend to maintain the <em>flatness of water overcoming</em> the push by the legs of the strider.  

When the insect’s weight pulls it down , the surface tension pushes it upwards  overcoming this force of gravity. This is how<em> water striders move along the surface of water.  </em>

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Mkey [24]

Answer:

a. Rotational inertia: 5.21kgm²

b. Magnitude of it's angular momentum: 123.32kgm²/s

Explanation:

Length of the rod = 3.46m

Weight of the rod = 12.8 N

Angular velocity of the rod= 226 rev/min

a. Rotational Inertia (I) about its axis

The formula for rotational inertia =

I = (1/12×m×L²) + m × ( L ÷ 2)²

Where L = length of the rod

m = mass of the rod

Mass of the rod is calculated by dividing the weight of the rod with the acceleration due to gravity.

Acceleration due to gravity = 9.81m/s²

Mass of the rod = 12.8N/ 9.81m/s²

Mass of the rod = 1.305kg

Rotational Inertia =

(1/12× 1.305 × 3.46²)+ 1.305 ( 3.46÷2)²

Rotational Inertia =  1.3019115 + 3.9057345

Rotational Inertia = 5.207646kgm²

Approximately = 5.21kgm²

b. The magnitude of the rod's angular momentum about the rotational axis is calculated as

Rotational Inertia about its axis × angular speed of the rod.

Angular speed of the rod is calculated as= (Angular velocity of the rod × 2π)/60

= (226×2π) /60

= 23.67 rad/s

Rotational Inertia = 5.21kgm²

The magnitude of the rod's angular momentum about the rotational axis

= 5.21kgm²× 23.67 rad/s

= 123.3207kgm²/s

Approximately = 123.32kgm²/s

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