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kykrilka [37]
3 years ago
14

Which of the following effects is produced by the high surface tension of water? Which of the following effects is produced by t

he high surface tension of water? A water strider can walk across the surface of a small pond. Water flows upward from the roots to the leaves in plants. Evaporation of sweat from the skin helps to keep people from overheating. Lakes don't freeze solid in winter despite low temperatures. Organisms resist temperature changes, although they give off heat due to chemical reactions.
Physics
1 answer:
Mashcka [7]3 years ago
7 0

<u>Answer:</u>

<em>A water strider can walk along the surface of earth due to the surface tension of water. </em>

<u>Explanation:</u>

Fluids have a <em>tendency to shrink to minimum possible surface area</em> and this is called surface tension. It usually occurs due to the greater force of cohesion between molecules of same substance when compared to adhesive force between molecules of different substances. Objects with greater densities can float along water surface due to the <em>role played by surface tension. </em>

When insects walk along the water surface they  are pulled down due to gravity. But  the  force of attraction  between the legs of the insect and water molecules is minimal. Thus the surface tension would always tend to maintain the <em>flatness of water overcoming</em> the push by the legs of the strider.  

When the insect’s weight pulls it down , the surface tension pushes it upwards  overcoming this force of gravity. This is how<em> water striders move along the surface of water.  </em>

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Two friction disks A and B are brought into contact when the angular velocity of disk A is 240 rpm counterclockwise and disk B i
mel-nik [20]

Answer:

a) αA = 4.35 rad/s²

αB = 1.84 rad/s²

b) t = 3.7 rad/s²

Explanation:

Given:

wA₀ = 240 rpm = 8π rad/s

wA₁ = 8π -αA*t₁

The angle in B is:

\theta _{B} =4\pi =\frac{1}{2} \alpha _{B} t_{1}^{2}  =\frac{1}{2} (\frac{r_{A} }{r_{B} } )^{3} \alpha _{A} t_{1}^{2}=\frac{1}{2} (\frac{0.15}{0.2} )^{3} \alpha _{A} t_{1}^{2}

\alpha _{A} =8\pi (\frac{0.2}{0.15} )^{3} =59.57rad

w_{B,1} =\alpha _{B} t_{1}=(\frac{0.15}{0.2} )^{3} \alpha _{A} t_{1}=0.422\alpha _{A} t_{1}

The velocity at the contact point is equal to:

v=r_{A} w_{A} =0.15*(8\pi -\alpha _{A} t_{1})=1.2\pi -0.15\alpha _{A} t_{1}

v=r_{B} w_{B} =0.2*(0.422\alpha _{A} t_{1})=0.0844\alpha _{A} t_{1}

Matching both expressions:

1.2\pi -0.15\alpha _{A} t_{1}=0.0844\alpha _{A} t_{1}\\\alpha _{A} t_{1}=16.09rad/s

b) The time during which the disks slip is:

t_{1} =\frac{\alpha _{A} t_{1}^{2}}{\alpha _{A} t_{1}} =\frac{59.574}{16.09} =3.7s

a) The angular acceleration of each disk is

\alpha _{A}=\frac{\alpha _{A} t_{1}}{t_{1} } =\frac{16.09}{3.7} =4.35rad/s^{2} (clockwise)

\alpha _{B}=(\frac{0.15}{0.2} )^{3} *4.35=1.84rad/s^{2} (clockwise)

6 0
3 years ago
What is nuclear energy?
____ [38]

Answer: D. Energy released from atoms.

7 0
3 years ago
A 2.0 m length of wire is made by welding the end of a 120 cm long silver wire to the end of an 80 cm long copper wire. Each pie
Levart [38]

<u>Explanation</u>:

Resistivity of silver wire =1.47 e-8 ohm meter

Resistivity of copper wire = 1.72 \mathrm{e}-8 \text { ohm meter }

Resistance = Resistivity *length/cross sectional area

R=\rho_{L / A}

So,

\begin{aligned}&I=A\left(V / P_{A g} L_{A g}+P_{C u} L C_{U}\right)\\&1=8104 \mathrm{A}\end{aligned}

For E calculation

For copper

E = resistivity * current density

E = Resistivity * current/area

E=4.9298 \mathrm{V} / \mathrm{m}

For silver

E=4.213 \mathrm{V} / \mathrm{m}

Potential difference $=E^{*} L$

For silver

Potential difference = 4.213^{*} 1.2=5.055 \mathrm{V}

For copper

Potential difference =3.9438 \mathrm{V}

7 0
3 years ago
V = d/t please help with my physics question!
Assoli18 [71]

Answer:

313, 0.60 s

Explanation:

wavelength

= speed/frequency

= 340/520

= 0.6538 m

Number of wavelengths

= 205/0.6538

= <u>313</u> (whole number)

Time delay

= distance/speed

= 204/340

= <u>0.60 s</u>

7 0
3 years ago
I hope some one can help me!
zloy xaker [14]
Given that:
μ = 36 
<span>σ = 3 
</span>
<span>Standardize x to z = (x - μ) / σ </span>
<span>P( 39 < x < 42) = P[( 39 - 36) / 3 < Z < ( 42 - 36) / 3] </span>
<span>P( 1 < Z < 2) = P( x < 2) - P( x < 1)
                     = 0.9772 - 0.8413
                     = 0.1359 </span>

<span>(0.1359)(30)
= 4.0777
= 4 days</span>
7 0
3 years ago
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