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3 years ago

What is true about the completly simplified difference of the polynomials

Mathematics

1 answer:

Ivan3 years ago

3 0

Answer: the difference has 4 terms and a degree is 6.

Step-by-step explanation

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Consider the two trinomials

Brilliant_brown [7]

Answer:

Step-by-step explanation:

Add the trinomials it becomes a binomial 7x removes. Becomes 2x^4-7(2x^2-7)(x^2+1)

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3 years ago

Is (-3.4) a rational number? And why is (-3.4) a rational number?

KIM [24]

Answer:

Yes

Step-by-step explanation:

a rational number is a number that can be written as a fraction. Rational numbers are all real numbers, and can be positive or negative. A number that is not rational is called irrational. Most of the numbers that people use in everyday life are rational. These include fractions and integers.

- 3.4 is a integer and also a rational number.

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3 years ago

1 000 sheets of computer paper for $8.95 find unit rate

Novosadov [1.4K]

The answer is 2.5 plus the sum of 1000

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3 years ago

A circle has a radius of 6. An arc in this circle has a central angle of 48 degress. What is the length of the arc?

notsponge [240]

Answer: $1.6\pi$

Step-by-step explanation:

If a circle has a radius of 6, then the perimeter of the circle is 12pi, or about 37.68. A circle has 360 degrees. Thus, the arc takes up 48/360 of the circle. Thus, simply multiply $\frac{48}{360} * 12\pi$ to get 5.024 or 1.6pi.

Hope it helps <3

3 0

3 years ago

Read 2 more answers

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

<u>Right part:</u>

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

3 0

3 years ago