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velikii [3]
3 years ago
6

the width of a rectangle is 3 in less than its length. The perimeter of the rectangle is 26 in. What is the width of the rectang

le?
Mathematics
1 answer:
____ [38]3 years ago
4 0

Answer:

ok so if we take length to be x we know width is x-3

the perimeter is the total length of sides, if you look at a rectangle you can see it has 4 sides with 2 length and 2 width. so perimeter is 2 times (x + x-3) = 26.

2x -3 = 13, 2x = 16, x = 8, 8 is length

the width is then 8-3 = 5.

Length = 8, width = 5.

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2x-py=5 and 4x+5y+q=0.
Mademuasel [1]

Answer:

q = 1 and p = 3

Step-by-step explanation:

Since we are already given the value of x and y, then it will be easy to get what p and q is. What is needed to be done is just to insert the values of x and y in both equations

For equation 1

2x -py = 5

insert x = q and y = -1

2(q) -p(-1) = 5

2q + p = 5

for the second equation, we do same

4x + 5y + q = 0

insert x = q and y = -1

4(q) + 5(-1) + q = 0

4q -5 + q = 0

5q = 5

q = 5/5 = 1

Recall from above, 2q + p = 5

Insert q = 1, we have ;

2(1) + p = 5

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p = 5-2

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7 0
3 years ago
Solve quadratic equation 10x^2+x-2=0
zhuklara [117]

Answer:

\{-\frac{1}{2} \} \cup \{\frac{2}{5}\}

Step-by-step explanation:

10x^2 + x - 2 = 0; \\ a = 10, b = 1, c = -2; \\ D = b^2 - 4ac = 1^2 - 4 * 10 * (-2) = 1 + 80 = 81 = 9^2, > 0; \\ x_{1, 2} = \frac{-b \pm \sqrt{D}}{2a} = \frac{-1 \pm \sqrt{9^2}}{2 * 10} = \frac{-1 \pm 9}{20} = \left \ [ {{\frac{-1 - 9}{20} = -\frac{10}{20} = -\frac{1}{2}  } \atop {\frac{-1 + 9}{20} = \frac{8}{20} = \frac{2}{5}}} \right.

8 0
2 years ago
Please help. I need the answer to the question circled in red. thanks!!​
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<em>35 units</em>

Step-by-step explanation:

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