Answer:
a) 0.50575,
b) 0.042
Step-by-step explanation:
Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.
If the first time you can buy good products, the next time you can buy good products is 0.85; (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).
And if the last time I bought a bad product, the next time I bought a good one is 0.6. Calculate the probability that:
a) All three times the person bought good goods.
P(Good on 1st shopping event AND Good on 2nd shopping event AND Good on 3rd shopping event) =
P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) =
(0.7)(0.85)(0.85) =
0.50575
b) Only the second time that person buys a bad product.
P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) =
P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) =
(0.7)(1-0.85)(1-0.6) =
(0.7)(0.15)(0.4) =
0.042
Answer:
aaaaa
Step-by-step explanation:
0.5, you would divide 0.375 to cancel out the height and then divide 0.75 (the new volume after you divided 0.375 by the height) by 1.5 to cancel out the x
<h3><u>Distance travelled each day is</u> : </h3>
<h3><u>Explanation</u> : </h3>
Distance travelled in 14 days is : 456.4 km
And if he travels same Distance each day, so let the Distance travelled on each day be x
According to question ~
So, he travels 32.6 km per day
Answer:
28+12x
Step-by-step explanation:
Multiply 7 with 4
Multiply 3x with 4
