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Andre45 [30]
3 years ago
11

Please could someone help

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0
1. Simplify= xy^3
2. Factorise= (2x+1)(2x-1)
3. 
4. 
5. Estimate= 415.96
6. Highest Common Factor
70= -70,-35,-14,-10,-7,-5,-2,-1,1,2,5,7,10,14,35,70
98= -98,-49,-14,-7,-2,-1,1,2,7,14,49,98
7. Expand: 4-4x+x^2 Simplify: x^2-4x+4
8. 
9. This is actually the easiest you take both the mass and volume and divide them :) which would be 500g<span>÷25cm^3=20g/cm3 </span>
10. 

The ones I didn't answer I am not sure about and don't wanna give you any wrong answers :) Hope I helped though!
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7% of what lenght is 200 ft?
Nastasia [14]
If you would like to solve 7% of what length is 200 ft, you can calculate this using the following steps:

7% of what length is 200 ft
7% * x = 200
7/100 * x = 200      /*100/7
x = 200 * 100 / 7
x = 2857 ft

Result: 7% of 2857 ft is 200 ft.
5 0
3 years ago
Read 2 more answers
Hello, can you explain this topic im in 6th grade ​
Andrew [12]

Hello there I hope you are having a great day :)

<u>The Topic Shifting digits:</u>

Shifting digits - Putting a digit in a different place. For a example Take the number 358 you would exchange the number from the hundreds that would equal 838 this meaning that you what to make a bigger number than a small one.

Examples:

1. 358 equal 838

2. 204 equal 402

3. 188 equal 881

You are just making them smaller to a greater number :)

Hopefully that helps you :)

 

<u></u>

5 0
3 years ago
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Given the equation P = 2w + 2l solve for w. A) 2w = P - 2l B) w = 2l + P 2 C) w = P -2l 2 D) w = 2l - P 2
Artist 52 [7]
w = - 1\frac{P}{2}



Hope that helps, Good luck!
5 0
3 years ago
Read 2 more answers
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
Can someone find x for these questions
Maurinko [17]

Answer:

8, 36, -12

Step-by-step explanation:

Q2

41 = 8x - 23

8x = 41 + 23

8x = 64

x = 8

Q4

11 = x/2 - 7

22 = x - 14

22 + 14 = x

x = 36

Q6

3(x - 8) = -60

x - 8 = -20

x = -12

8 0
3 years ago
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