3 years ago

All of the following are classified as acids except

Chemistry

1 answer:

Neporo4naja [7]3 years ago

7 0

I think D im not completely sure

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A fossilized leaf contains 24% of its normal amount of carbon 14. how old is the fossil (to the nearest year)? use 5600 years as

sergij07 [2.7K]

The Half life is the time taken for a radioisotope or a radioactive substance to decay by half its original amount. The half life of carbon 14 is 5600 years.
Original mass is 100%
Remaining amount is 24%
Therefore; 0.24 = 1 × (1/2)^n
n = log 0.24/log 0.5
= 2.06
therefore, the age of the fossil is 5600×2.06
= 11529.8
≈ 11529 years

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4 years ago

2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4

agasfer [191]

Answer:

$d=4.24x10^{-4}\frac{lb}{in^3}$

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

$d=\frac{m}{V}$

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

$m=552.4g-464.7g=87.7g$

So that we are now able to calculate the density in g/mL first:

$d=\frac{87.7g}{27.8mL}=3.15g/mL$

Now, we proceed to the conversion to lb/in³ by using the following setup:

$d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}$

Regards!

6 0

3 years ago

Equal masses of substance A and substance B are at 25°C. Substance A has a lower specific heat capacity than substance B. If 50

liraira [26]

Dang bro that stuff is really hard I’m defiantly on a lower grade lol

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3 years ago

What tool did scientist use to first study the Earth’s interior

IgorC [24]

Seismic waves hope this helps.

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3 years ago

Fill in the coefficients that will balance the following reaction: a0Na + a1H2O → a2NaOH + a3H2

Alexandra [31]

Hey there ! :

2 Na + 2 H2O = 2 NaOH + 1 H2

Sodium + Dihydrogen Monoxide = Natriumhydroxid + Hydrogen

Coefficients:

Reagents : Na = 2
H2O = 2

Products : NaOH = 2
H2 = 1

4 0

3 years ago

Read 2 more answers