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3 years ago

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All of the following are classified as acids except

1 answer:

Neporo4naja [7]3 years ago

7 0

I think D im not completely sure

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A vehicle travels at the same speed from point a to point b then from point b to point a. which statement is correct?

ss7ja [257]

D would be the answer.
Hope this helps

8 0

3 years ago

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If the temperature of the earth's layers increases by about 90 degrees fahrenheit for every 1 mile from the surface and you are

bogdanovich [222]

The rate of change of the temperature of the Earth's surface is given to,
90°F/mile
To determine the temperature x miles away from the surface, we multiply the depth by the given rate. This will give us the answer of,
T = (90°F/mile)(90 mile)
= 8100°F
Thus, the temperature 90 miles deep in the Earth's surface is equal to 8100°F.

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3 years ago

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Calculate the weight percent of ascorbic acid in a tablet of Vitamin C from the following data:A 80 mg sample of a crushed Vitam

Lina20 [59]

Answer:

The Answer is 88%

Explanation:

The balanced ionic equation of the reaction

$IO^{3- }+ 8 I^- + 6 H^+ => 3 I^{3- }+ 3 H_2O$

$I^{3-} + 2 S_2O_3^{2-} => 3 I^- + S_4O_6^{2-}$

$C_6H_8O_6 + I^{3- }+ H_2O => C_6H_6O_6 + 3 I^- + 2 H^+$

Looking at the above reactions

The original number of moles of $I^{3-}$ = 3 × number of moles of $IO^{3-}$

= 3 × volume × concentration of $KIO_3$

Note: The formula for number of moles is volume × concentration

$=3 * \frac{40}{1000} * 0.00653 =0.000784$ mol

The number of moles of $I^{3-}$ left after its reaction with ascorbic acid

= $\frac{1}{2}$ x moles of $S_2O_3^{2-}$

= $\frac{1}{2}$ x volume x concentration of $S_2O_3^{2-}$

$= \frac{1}{2} * \frac{15}{1000} * 0.0510 =0.000383 \ mol$

Note: The division by 1000 is to convert mill liter to liter

Moles of ascorbic acid = moles of $I^{3-}$ reacted

$= initial \ moles \ of \ I^{3-} \ - remaining \ moles \ of \ I^{3-}$

$=0.000784 - 0.000383$

$=0.000401 \ mols$

$Mass = moles \ * molar \ mass$

Hence

Mass of ascorbic acid = moles of ascorbic acid × molar mass of ascorbic acid

$= 0.000401* 176.12 = 0.07055\ g$

$= 70.55\ mg$

Weight% of ascorbic acid = mass of ascorbic acid/mass of sample x 100%

= 70.55/80 × 100%

= 88.1%

3 0

4 years ago

A chemist determined by measurements that 0.0650 moles of gallium participated in a chemica reaction. Calculate the mass of gall

frosja888 [35]

Answer:

4.53gm

Explanation: n=m/M

n is # of moles

m is mass

M is molar mass

so m=n*M when you rearrange the equation

7 0

3 years ago

Select the correct answer.

Lunna [17]

Answer:

B or C

Explanation:

I'm not very sure sorry

6 0

4 years ago