Answer:
The enthalpy of the reaction of the reaction asked in the question is 265.2 kJ.
Explanation:
...(1)
..(2)
...(3)
(1)+(2)
...(4)
On reversing the equation (4)we get (3):
The enthalpy of the reaction of the reaction asked in the question is 265.2 kJ.
The element number of Fe is 26, which means that the number of neutrons of the following isotopes is:
<span>53-Fe: 27 </span>
<span>54-Fe: 28 </span>
<span>56-Fe: 30 </span>
<span>57-Fe: 31 </span>
<span>58-Fe: 32 </span>
<span>59-Fe: 33 </span>
<span>Because 53-Fe has too few neutrons when compared to the other isotopes we can rule out any decay that involves losing a neutron: (alpha decay, beta decay) So, this isotope will prefer to decay by electron capture or positron emission (assuming the system has about 1 MeV to spare), but in each case the product will be the same: 53-Mn (long-lived radioisotope). </span>
Added together = 159.7 grams for one mole of Fe2O3<span>. That is moles of hematite, but the question is about iron. We can see there are </span>two<span> iron atoms for every hematite molecule. So the number (moles) of iron atoms is twice the moles of the hematite molecules.
so depending on how much you initially have will determine the answer</span>
the answer is false at lest that is what i know
CH4 : H2O
1 : 2
number of moles of H2O = 1.00 x 2
number of moles of H2O = 2.00mol
mass = number of moles x molar mass
mass of H2O = 2.00 x (1 + 1 + 16)
mass of H2O = 36g
