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3 years ago

Which of the substances in the chart has the least density?

Chemistry

1 answer:

3241004551 [841]3 years ago

3 0

Answer:
Option-D (Piece of Wood) is the correct answer.

Explanation:
Density is related to mass and volume as,

Density = Mass / Volume
For Wood,
Density = 42.5 / 50

Density = 0.85

You can calculate remaining densities by yourself. Among all the density of Piece of Wood is the least.

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Which of the following particles combine to form molecules?

solniwko [45]

Answer: i think its protons and electrons but it also might just be atoms because protons and electrons make atoms when there are also neutrons

Explanation:

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3 years ago

294 g of potassium dichromate contains 52 g of chromium and 39 g of potassium. What is the mass percent of oxygen in the compoun

IgorLugansk [536]

69.047% is the answer to this question

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3 years ago

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What is the de Broglie wavelength (in meters) of a 45-g golf ball traveling at 72 m/s?

Cerrena [4.2K]

Answer: The de broglie wavelength is $2.037 \times 10^{-34} m$ .

Explanation:

Calculate $\lambda = \frac{h}{p}$ as follows.

$\lambda = \frac{h}{p}$

where,

h = plank's constant = $6.6 \times 10^{-34} m^{2} kg/s$

p = momentum = $mass \times velocity$

Putting the values in the formula as follows.

$\lambda = \frac{h}{mass \times velocity}$

= $\frac {6.6 \times 10^{-34} m^{2} kg/s}{0.045 kg \times 72 m/s}$

= $2.037 \times 10^{-34} m$

Thus, the de broglie wavelength is $2.037 \times 10^{-34} m$ .

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3 years ago

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A gas is at a pressure of 3.70 atm. What is this pressure in kilopascals?

Yanka [14]

Answer:
= 374.90 kPa

Calculation:
As we know atm and kiloPascal are related to each other as,

1 atm = 101.325 kPa
So,
3.70 atm = X
Solving for X,
X = (3.70 atm × 101.325 kPa) ÷ 1 atm

X = 374.90 kPa

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3 years ago

What is the value for ∆Soreaction for the following reaction, given the standard entropy values? 2H2S(g) + SO2(g) 3Srhombic(s) +

Mademuasel [1]

Answer: $\Delta S^{0}$ for the reaction is -186.75 J/K

Explanation:

Change in entropy ( $\Delta S^{0}$ ) for the given reaction under standard condition is given by-

$\Delta S^{0}$ = $[3\times S_{rhombic}^{0}_{(s)}]+[2\times S_{H_{2}O}^{0}_{(g)}]-[2\times S_{H_{2}S}^{0}_{(g)}]-[1\times S_{SO_{2}}^{0}_{(g)}]$

So $\Delta S^{0}$ = $[3\times 31.8 J/K.mol]+[2\times 188.825 J/K.mol]-[2\times 205.79 J/K.mol]-[1\times 248.22 J/K.mol]$ = -186.75 J/K

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3 years ago