1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mila [183]
3 years ago
5

The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the fun

ction mc002-1.jpg. Which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall
Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0
I believe the correct answer from the choices listed above is option D. The expression that could be used to determine the average rate at which the object falls during the first 3 seconds of its fall would be <span> (h(3)-h(0))/3. Average rate can be calculated by the general formula:

Average rate = (change in y-axis) / (change in x-axis)

In this case,

</span>Average rate = (change in height) / (change in time)
You might be interested in
Consider the equation 30÷x=6.
8090 [49]
Part A : 30 - x - x - x - x - x - x = 0

^ since 30 divided by 5 is 6, that answer is the same as doing 5 + 5 + 5 + 5 + 5 + 5

- pls comment & correct me if i did smth wrong :’)
7 0
2 years ago
Read 2 more answers
A flower shop makes 5 bouquets with 18 flowers in each bouquet. They make 7 bouquets with 12 flowers in each bouquet.
Anettt [7]

Answer:

174

Step-by-step explanation:

thanks for the help guys

7 0
2 years ago
Assuming that n 1 , rewrite the compound interest equation B t 900 1.185 t in the general form.
Rufina [12.5K]
\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}&#10;\end{array}\\&#10;t=year&#10;\end{cases}

\bf 1.185\implies 1+0.185\qquad\quad and\quad n=1&#10;\\\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}\implies A=P\left(1+0.185\right)^{nt}\implies A=P\left(1+\frac{0.185}{1}\right)^{1\cdot  t}

so, the percentage of the rate is 0.185, what's that as a percentage? well, 0.185 * 100, 18.5%.
3 0
3 years ago
Ian is going to water his plants is it reasonable to say he will fill the watering can with 3 liters of water explain
Y_Kistochka [10]
This is possible for a smaller watering can. 3 liters is about 3/4 of a gallon (imagine a jug of milk).

It is equivalent to 3000 ml, which would also be 100 ounces of water.(5 -20 oz bottles of water).
4 0
3 years ago
Sarah drove 40 miles per hour . In 3 hours sarah drove 120 miles . Which is a vaild proportion to represent the problem?
antoniya [11.8K]

Answer:


Step-by-step explanation:

1/40=3/120

5 0
3 years ago
Read 2 more answers
Other questions:
  • a magazine has 5580000 subscribers this year. This number is down 7% from last year. How many subscribers were there last year?
    6·2 answers
  • Multiply (−4) × (−2) × (−5).<br><br> A. −40<br> B. −8<br> C. 8<br> D. 40
    7·2 answers
  • Find the domain and range of <img src="https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B2x%7D%7B1%20%2B%20x%5E2%7D" id="TexFormula1"
    5·1 answer
  • The actual length of the rectangle below is 41 cm. Using the scale drawing below, find the actual width.
    5·2 answers
  • Megan answered 18 questions correctly on a test. That is 75% of the total number of questions. How many questions were on the te
    10·1 answer
  • (-3)-(-19) I got -22 am I right?
    7·2 answers
  • Dicriminant of x² – 49 = 0
    15·1 answer
  • The value of 12pi over 10pi times 5pi Over 6pi is closest to the whole number (blank). Find the blank
    13·1 answer
  • Help me i'm not sure about this one
    13·2 answers
  • The mean score on a physics test was 75 points. Amy’s score was 67 points, which was 2 standard deviations below the mean.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!