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Mila [183]
3 years ago
5

The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the fun

ction mc002-1.jpg. Which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall
Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0
I believe the correct answer from the choices listed above is option D. The expression that could be used to determine the average rate at which the object falls during the first 3 seconds of its fall would be <span> (h(3)-h(0))/3. Average rate can be calculated by the general formula:

Average rate = (change in y-axis) / (change in x-axis)

In this case,

</span>Average rate = (change in height) / (change in time)
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Let u= &lt;4,3&gt;. Find the unit vector in the direction of u, and write your answer in component form.
aksik [14]
Take the vector u = <ux, uy> = <4, 3>.

Find the magnitude of u:

||u|| = sqrt[ (ux)^2 + (uy)^2]

||u|| = sqrt[ 4^2 + 3^2 ]

||u|| = sqrt[ 16 + 9 ]

||u|| = sqrt[ 25 ]

||u|| = 5

To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is

u/||u||

u * (1/||u||)

= <4, 3> * (1/5)

= <4/5, 3/5>

and there it is.

Writing it in component form:

= (4/5) * i + (3/5) * j

I hope this helps. =)
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3 years ago
DESPERATE WILL GIVE BRAINLIST AND THANKS
Illusion [34]

Answer: What you must do for this case is to graph each of the ordered pairs that you have in the table to obtain the dispersion chart. Note that in your table you have eight ordered pairs, therefore, your scatter chart must have eight pairs.

Step-by-step explanation:

7 0
2 years ago
Find the surface area of the part of the sphere x2+y2+z2=81 that lies above the cone z=x2+y2−−−−−−√
TiliK225 [7]
Parameterize the part of the sphere by

\mathbf s(u,v)=(9\cos u\sin v,9\sin u\sin v,9\cos v)

with 0\le u\le2\pi and 0\le v\le\dfrac\pi4. Then

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=81\sin v\,\mathrm du\,\mathrm dv

So the area of S (the part of the sphere above the cone) is given by

\displaystyle\iint_S\mathrm dS=81\int_{v=0}^{v=\pi/4}\int_{u=0}^{u=2\pi}\sin v\,\mathrm du\,\mathrm dv=81(2\pi)\left(1-\dfrac1{\sqrt2}\right)=(162-81\sqrt2)\pi
4 0
3 years ago
prakrit bought a pack of paper for 5.69 and printer toner for 9.76 he paid for with a 20 what was his change
natka813 [3]
$4.55 Add 5.95 and 9.76. You should get 15.45. Then you do 20-15.45=4.55
3 0
3 years ago
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Given figure LMNO ~ figure STUV, what is the value of x? LMNO has 4.1 in and 22. in and STUV has 12.3 in
Furkat [3]
Set up a proportion:

4.1/22 = 12.3/x

Cross multiply:

4.1 * x = 22 * 12.3

4.1x = 270.6

Divide 4.1 to both sides:

x = 66
7 0
3 years ago
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