Answer:
<em>Alex sold 330 white chocolate bars</em>
Step-by-step explanation:
let the milk chocolate candy be x and the white chocolate candy be y. then
then 2x+3y=990----1)
x+y=330-----2)
from eq 2) ⇒ x=330-y---------3)
Putting eq 3 in eq 1
2(330-y) +3y=990
660-2y+3y=990
y=990-660=330-----------4)
Putting eq4 in eq1
2x+3(330)=990
2x+990=990
2x=990-990
2x=0
x=0---------------------------5)
Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Answer:
the building would be 280 feet (judging on how this is worded.)
Step-by-step explanation:
you are already 100 meters from the base ( bottom) of the building so you add 180 as you are 180 ft from the top of the building. 100 + 180 is equal to 280.
