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masha68 [24]
3 years ago
8

How could a food web based in water be connected to a food web based on land? Give an example.

Physics
2 answers:
Aloiza [94]3 years ago
6 0
A land animal like a kingfisher hunts fishes and fishes search for planktons or any other kind of plant.
Serggg [28]3 years ago
4 0
Land animals could eat water animals For example, a bear could eat salmon from the river and that could be connected to organisms from water to land
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if a bullet fired beneath the water, straight up, breaks through the surface at a speed of 25m/s, how high will the bullet be af
Doss [256]

Answer:

32 m and -2.4 m/s

Explanation:

Given:

v₀ = 25 m/s

t = 2.8 s

a = -9.8 m/s²

Find: Δy, v

Δy = v₀ t + ½ at²

Δy = (25 m/s) (2.8 s) + ½ (-9.8 m/s²) (2.8 s)²

Δy = 31.6 m

v = at + v₀

v = (-9.8 m/s²) (2.8 s) + 25 m/s

v = -2.44 m/s

Rounded to two significant figures, the bullet reaches a height of 32 m and a velocity of -2.4 m/s.

8 0
3 years ago
Metric system please help me I don’t know how to do this
amm1812

Answer:

11. 6700L

12. 0.0000238

13. 1805

14. 3800

15. 1400

16. 0.01428

17. 0.0003585

18. 0.0415

19. 4060.0

20.0.105

8 0
2 years ago
hydraulic lift is to be used to lift a 2100-kg weight by putting a weight of 25 kg on a piston with a diameter of 10 cm. Determi
trasher [3.6K]

Answer:

840 cm

Explanation:

Note: A hydraulic press operate based on pascal's principle.

From pascal's principle

W₁/d₁ = W₂/d₂...................... Equation 1

Where W₁ and W₂ are the first and second weight, and d₁ and d₂ are the  first and second diameter of the piston.

make d₁ the subject of the equation

d₁ = W₁×d₂/W₂................ Equation 2

Given: W₁ = 2100 kg, W₂ = 25 kg, d₂ = 10 cm = 0.1 m.

Substitute these values into equation 2

d₁ = 2100(0.1)/25

d₁ = 8.4 m

d₁ = 840 cm

3 0
3 years ago
Which of these is a characteristic of the Milky Way galaxy
IRINA_888 [86]

Answer:

A

Explanation:

3 0
2 years ago
What is the speed of a transverse wave in a rope of length 3. 1 m and mass 86 g under a tension of 380 n?
Nitella [24]

117 m/sec is the speed of a transverse wave in a rope of length 3. 1 m and mass 86 g under a tension of 380 n.

The wave speed v is given by

v= √τ/μ

​where τ is the tension in the rope and μ is the linear mass density of the rope.

The linear mass density is the mass per unit length of rope :

μ= m / L = (0.086 kg)/(3.1 m)=0.0277 kg/m.

v= \sqrt{ \frac{380 N}{0.0277 kg/m}}  = 117.125 m/sec (approx. 117 m/sec

In physics, a transverse wave is a wave whose oscillations are perpendicular to the direction of the wave's advance. This is in contrast to a longitudinal wave which travels in the direction of its oscillations. Water waves are an example of transverse wave.

Transverse waves commonly occur in elastic solids due to the shear stress generated; the oscillations in this case are the displacement of the solid particles away from their relaxed position, in directions perpendicular to the propagation of the wave. These displacements correspond to a local shear deformation of the material. Hence a transverse wave of this nature is called a shear wave. Since fluids cannot resist shear forces while at rest, propagation of transverse waves inside the bulk of fluids is not possible.

Learn more about Transverse waves here : brainly.com/question/13761336

#SPJ4

3 0
2 years ago
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