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Elan Coil [88]
2 years ago
14

Select the arrangement of electromagnetic radiation which starts with the lowest wavelength and increases greatest wavelength. M

ultiple Choice radio, ultraviolet, infrared, gamma rays gamma rays, ultraviolet, infrared, radio radio, infrared, ultraviolet, gamma rays gamma rays, infrared, radio, ultraviolet gamma rays, radio, ultraviolet, infrared
Physics
2 answers:
Scorpion4ik [409]2 years ago
8 0

Answer:

gamma rays, ultraviolet, infrared, radio

Explanation:

Because on the Electromagnetic spectrum wavelength increases from the gamma end to radio end and frequency decrease in that order

Fiesta28 [93]2 years ago
7 0

Answer:

radio → infrared → ultraviolet → gamma

Explanation: yeaaahhh its c

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On a frictionless surface how much force is necessary to accelerate a 0.49 kg object to the left at 4.8 m/s2?
Alenkasestr [34]

Answer:

<h2>2.35 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

force = 0.49 × 4.8 = 2.352

We have the final answer as

<h3>2.35 N</h3>

Hope this helps you

8 0
2 years ago
Hello, how to do qn 5?:)l
Hitman42 [59]

Answer:

A

Explanation:

Please see the attached picture for the full solution.

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The main advantage banking services offer is?
KATRIN_1 [288]
In short, and in general:

Advantages

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7 0
3 years ago
A circular window of 30 cm diameter in a submarine can withstand a maximum force of 5.20 × 105 N. The maximum depth in a lake to
Svetach [21]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

         F = 5.20 \times 10^{5} N

         g = 9.8 m/s

         radius = \frac{diameter}{2}

                    = \frac{30 cm}{2} = 15 cm = 0.15 m   (as 1 m = 100 cm)

Formula to calculate depth is as follows.

        F = \rho \times g \times h \times A

or,      h = \frac{F}{\rho \times g \times A}        

       h = \frac{5.2 \times 10^{5}}{1000 \times 9.8 \times (3.1416 \times (0.15 m^{2})}

           = 751 m

Thus, we can conclude that the maximum depth in a lake to which the submarine can go without damaging the window is closest 750 m.

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3 years ago
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