If the net force on object A is 5 N and the net force on object B is 10 N, then object B will accelerate more quickly than object A provided the mass of both objects are same.
Answer: Option C
<u>Explanation:
</u>
According to Newton’s second law of motion, any external force applied on an object is directly proportional to the mass and acceleration of the object. In order to state this law in terms of acceleration, it is stated that acceleration exhibited by any object is directly proportional to the net force applied on the object and inversely proportional to the mass of the object as shown below:
So if two objects A and B are identical which means they have same mass, then the acceleration attained by the object will be directly proportionate to the net forces exerted on the objects only.
Thus if the force applied is more for one object, then the object will be exhibiting more acceleration compared to the other one. So as object B is experiencing a net force of 10 N which is greater than the net force experiences by object A, then the object B will be accelerating more quickly compared to the object A's acceleration.
Answer:
B. 3
Explanation:
The half-life of a radioisotope is the time it needs for the mass of the radioisotope to halve with respect to its original value.
In this problem, the initial mass of the radioisotope at t=0 is
m0 = 50.0 mg
We see that after t = 1 min, the mass of the isotope is
m(1 min) = 25.0 mg
so, exactly half the initial mass: this means that 1 minute is exactly the half-life of this radioisotope.
So, the amount of mass left after each minute is the following:
m (1 min ) = 25.0 mg (1 half-life)
m (2 min) = 12.5 mg (2 half-lives)
m (3 min) = 6.25 mg (3 half-lives)
so, when we are left with 6.25 mg of isotope, 3 minutes have passed, which means that 3 half-lives have passed.
Answer:
length is 23.228091 m
Explanation:
Given data
radius = 0.791 mm = 0.791 × 
m
current = 9.25 A
voltage = 1.20 × 10² V
to find out
resistance and length of wire
solution
we know the resistance formula that is
resistance = voltage / current
resistance = 1.20 × 10² /9.25
resistance = 12.97
so resistance is 12.97 ohm
and length of nichrome wire formula is
length = resistance × area / specific resistance of wire
so specific resistance of wire we know = 1.1 × 
and area = 
× r² = × (0.0791× )²
area = 1.97 ×
length = 12.97 × 1.97 × / 1.1 ×
so length is 23.228091 m
