Answer:
c) Check to see if there's a better medication for the patient's problem.
d) Dispense an extra dose to save the patient from having to return in case of loss or damage to one of the doses.
e ) Compare the label on the medication with the order from the physician .
<h3><u>Answer;</u></h3>
= 49.42 g
<h3><u>Explanation;</u></h3>
The equation for the reaction between Lead (ii) nitrate and sodium iodide;
Pb(NO3)2(aq) + 2 NaI(aq) ---> 2NaNO3(aq) + PbI2(s)
The precipitate formed in this equation is Lead iodide
We first calculate the moles of lead nitrate;
Moles = mass/molar mass
= 35.5 g/ 331.2 g/mol
= 0.1072 moles
The mole ratio of Pb(NO3)2 : PbI2 is 1 : 1
Therefore; the number of moles of lead iodide is 0.1072 moles
Mass = moles × molar mass
= 0.1072 moles × 461.01 g/mol
<u>= 49.42 g</u>
Answer:
Lithium
Explanation:
Lithium is an alkali metal. This means that lithium is expected to be a member of the group one elements on the periodic table.
The group one elements ionize by losing one electron. Hence, the form univalent positive ions after ionization.
Lithium has 3 electrons, 2 belonging to the k shell with the valence L having the other electron. Upon ionization, it forms the ion Li+.
This means it has lost the electron in the valence shell probably through an ionic transfer. This means the only electron it has is in the S shell, which is of a smaller size when compared to elements having multiple rings of shell.
It is expected that negative ions become larger when they ionize as they receive more electrons while that of metals I.e positive electrons shrink when they ionize as they are givers of electrons.
Answer:
P.E = 493920 j
Explanation:
Given data:
Mass = 1200 kg
height = 42 m
Potential energy = ?
Solution:
Formula:
<em>P.E = mgh</em>
Now we will put the values in formula.
g = 9.8 m/s²
P.E = 1200 Kg × 9.8 m/s²× 42 m
P.E = 493920 Kg.m²/s²
Kg.m²/s² = j
P.E = 493920 j
