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Bess [88]
3 years ago
9

(only reply if you know the answer or get reported) Please solve this ty​

Chemistry
1 answer:
kolezko [41]3 years ago
4 0

Answer:

7) 50 8)4

Explanation:

I answered the question what do you want to gave me

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Check out this app! It's millions of students helping each other get through their schoolwork. https://brainly.app.link/qpzV02Ma
marishachu [46]

Answer:

why did you post a link to brainly when we are on brainly already??????

Explanation:

8 0
3 years ago
Wherever there is an action force, there must be a reaction force that
Fittoniya [83]

Answer:

is equal to the action force , but acts in the opposite direction.

Explanation:

  • All you need to solve is apply Newton's third law.

It states that

  • Every action has an equal and opposite reaction

Or

\\ \tt\bull\rightarrowtail F_A=-F_A

4 0
3 years ago
To a 25.00 mL volumetric flask, a lab technician adds a 0.250 g sample of a weak monoprotic acid, HA , and dilutes to the mark w
Basile [38]

Answer: The number of moles of the weak acid in the solution is 0.00396

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      

a) {\text{Moles of}KOH=0.0846M\times 0.04683L=0.00396mol

The balanced chemical reaction is:

HA+KOH\rightarrow KA+H_2O  

1 mole of base uses = 1 mole of HA  

0.00396  moles of base use = \frac{1}{1}\times 0.00396=0.00396 moles of HA  

Thus the number of moles of the weak acid in the solution is 0.00396

6 0
3 years ago
What happens to the atoms and molecules in a substance as its temperature increases?
lana [24]
The molecules and atoms vibrate faster. As atoms vibrate faster the space between atoms also increases.
5 0
3 years ago
A mixture of MgBr2 and inert material is analyzed to determine the Mg content. First the mixture is dissolved in water. Then all
Mumz [18]

Answer:

9.24% the percent of Mg in the mixture.

Explanation:

Mass of silver bromide = 1.1739 g

Moles of silver bromide = \frac{1.1739 g}{188 g/mol}=0.006244 mol

1 mole of AgBr has 1 mole of bromine atom.Then 0.006244 moles AgBr has 0.006244 mole bromine atom.

Moles of bromine atoms = 0.006244 moles

Magnesium bromide has 2 moles of bromine atom.Then 0.006244 moles of bromine atoms will be in :

\frac{0.006244 mol}{2}=0.003122 mol

Magnesium bromide has 1 mole magnesium atom, then 0.003122 moles of magnesium bromide will have :

1\times 0.003122 mol=0.003122 mol magnesium atom

Mass of 0.003122 moles of magnesium :

0.003122 mol × 24 g/mol = 0.07493 g

Mass of the sample = 0.8107 g

Percentage of magnesium in the sample ;

=\frac{0.07493 g}{0.8107 g}\times 100=9.24\%

9.24% the percent of Mg in the mixture.

8 0
3 years ago
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