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Alecsey [184]
3 years ago
12

Which best describes a compound such as sodium chloride?

Chemistry
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

check it below

Explanation:

NaCl; Sodium Chloride is an ionic compound formed by sodium and Chlorine.

Ionic bond is very strong, It can't be separated back to sodium and chlorine just by physical change. Chemicals which are more reactive can displace ions, thus seperate it

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aliina [53]

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Explanation:

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3 years ago
What are two examples of a soulution?
Anni [7]
Which type of solution are you talking about?
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3 years ago
10. The density of aluminum is 2.7 g/cm². A 27g piece of aluminum will have<br> what volume?
kotegsom [21]
27g x 1cm^2/2.7g = answer in cm^2
Grams cancel out
3 0
3 years ago
I what process does a solid change directly into a vapor​
Marina86 [1]

Answer:

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7 0
3 years ago
Why can't methanol, CH3OH, be used as a solvent for sodium amide, NaNH2? Sodium amide is nonpolar and methanol is polar. Sodium
Elodia [21]

Answer: sodium amide undergoes an acid -base reaction

Explanation:

sodium amide is a ionic compound and basically exists as sodium cation and amide anion. Amide anion is highly basic in nature and hence as soon as  there is amide anion generated in the solution , Due to its very pronounced acidity it very quickly abstracts the slightly acidic proton available on methanol.

This leads to formation of ammonia and sodium methoxide.

Hence sodium amide reacts with methanol and abstracts its only acidic proton and form ammonia and sodium Methoxide.

Hence the 3rd statement is a corrects statement.

So we cannot use methanol for sodium amide because sodium amide itself would react with methanol and the inherent molecular natur of sodium amide would then change.

The 1st and 2nd statements both are incorrect because both the compounds methanol as well as sodium amide have dipole moments and hence are polar molecules.

The 4th statement is also incorrect as both the molecules have dipole moment and hence there would be ion-dipole forces operating between them.

The following reaction occurs:

NaNH₂+CH₃OH→NH₃+CH₃ONa

4 0
3 years ago
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