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Sholpan [36]
4 years ago
8

A tuning fork, frequency 385/sec produces resources with a closed tube 20cm long and 4cm in diameter what is the speed of sound?

[338m/s]
Physics
2 answers:
amm18124 years ago
8 0

f = frequency of the tuning fork = 385 Hz

L = length of the closed tube = 20 cm = 0.20 m

d = diameter of the closed tube = 4 cm = 0.04 m

v = speed of the sound = ?

for closed tube , fundamental frequency is given as

f = v/(4L)

rearranging the equation

v = 4 fL

inserting the values

v = 4 x 385 x 0.20

v = 308 m/s

hence the speed of sound comes out to be 308 m/s


fiasKO [112]4 years ago
3 0

Answer:

308 m/s

Explanation:

In a closed tube, the length of the tube (L) is related to the wavelength of the standing wave (\lambda) by the relationship

L=\frac{1}{4}\lambda

In this problem, the length of the tube is L=20 cm=0.20 m, so we can find the wavelength of the standing wave:

\lambda=4L=4 \cdot 0.20 m=0.80 m

And no we can find the speed of the sound wave by using the following equation:

c=\lambda f

where f=385 s^{-1} is the frequency of the wave. So, we find

c=(0.80 m)(385 s^{-1})=308 m/s

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Hello there! :)

\huge\boxed{\text{C. 293K}}

Room temperature is approximately 20°C.

We can automatically eliminate choices B and D since they are not equal to 20°C.

Since some choices use the Kelvin scale, we can convert from Celsius to Kelvin using a simple formula:

K = C° + 273

Find room temperature in degrees <u>Kelvin</u>:

K = 20° + 273

K = 293°

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3 years ago
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Atomic Mass Unit is the answer
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3 years ago
3. A car is traveling up a 3% grade, with the speed of 85mph, on a road that has good, wet pavement. A deer jumps out onto the r
solniwko [45]

Answer:

Explanation:

From the given information;

Let assume that:

the wheel radius = 15 inches

the driveline slippage = 3%;  &

the gear reduction ratio (overall) = 2.5 to 1

So; using the equation:

v_1= \dfrac{2 \pi r n_o (1 -i)}{\varepsilon_o}

v_1= \dfrac{2 \times 3.14 \times \dfrac{15}{12} \times \dfrac{85}{100} (1 -0.03)}{2.5}

v_1= \dfrac{2 \times 3.14 \times \dfrac{15}{12} \times \dfrac{85}{100} (0.97)}{2.5}

v_1 = 126.92 \ fp^3

frl = 0.01 ( 1+ \dfrac{v}{147}) \ if \ v \ is \ ft/sec

frl = 0.01 \Bigg( 1+ \dfrac{\dfrac{126.92 +(20)1.47 }{2}   }{147}\Bigg)

S = \dfrac{v_b ( v_1^r-v_2^r)}{2g(n_b \mu + frl \pm sin \ y}

where;

\mu = 0.6

291 = \dfrac{1.64( 126.92^2-29.9^2)}{64.4(n_b \times 0.6 +0.01532 +0.03}

n_b = 1.33  \to which \ is \ not \ possible

However;

n_b \mu = 1.33(0.6) = 0.80

\mu = 0.9 \to if the car's anti-clock breaking system did not fail

Thus;

n_b (0.9) = 0.80

n_b =\dfrac{ 0.80}{(0.9) }

n_b = 0.89

Hence, the distance is possible if the anti-clock breaking system did not fail.

4 0
3 years ago
The law of reflection states that if the angle of incidence is 40 degrees, the angle of reflection is ___ degrees.
Makovka662 [10]

Answer

40 degrees

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When waves hit a surface they get reflected. The law of reflection states that the angle of incidence is equal to the angle of reflection. In this case, the law of reflection tells us that if the angle of incidence is 40 degrees, the angle of reflection is 40 degrees.


5 0
3 years ago
a small bulb has a resistance of 2 ohm when cold it take up a current of 0.4 ampere from a source of 4v then start glowing? calc
Katarina [22]
The resistance of the bulb when it is cold is R=2 \Omega.

The resistance of the bulb when it is crossed by a current of I=0.4 A under a potential difference of V=4.0 V can be calculated by using Ohm's law:
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The reason for this difference in the resistance is the following: when the current passes through the bulb, the bulb heats up, and an increase in temperature in the filament of the bulb causes an increase in resistance of the filament. In fact, the resistance of a resistor increases as the temperature increases, because the atoms of the lattice of the material vibrate more (due to their greater energy) and therefore the electrons of the current are more likely to collide with them. As a result, the resistance of the material increases.
7 0
3 years ago
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