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3 years ago

The volume of a gas depends upon its mass. •True•False

Chemistry

2 answers:

tigry1 [53]3 years ago

7 0

False. the volume of a gas depends on the size of its container<span>
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algol133 years ago

6 0

False because i dos not matter

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9. Calculate the standard enthalpy of the 3rd reaction using the given data: A,H° = +52.96 kJ/mol AFH= -483.64 kJ/mol H2s)+I202

Mice21 [21]

Answer:

-586.56 kJ/mol is the standard enthalpy of the 3rd reaction.

Explanation:

$H_2(g) +I_2(s) \rightarrow 2 HI(g) ,\Delta H^{o}_{1}= +52.96 kJ/mol$ ...[1]

$2 H_2(g) + O_2(g)\rightarrow 2 H_2O(g),\Delta H^{o}_{2}=-483.64 kJ/mol$ ...[2]

$4 HI(g)+O_2(g)\rightarrow 2 I_2(s)+2 H_2O(g) ,\Delta H^{o}_{3} =?$ ..[3]

The unknown standard enthalpy of third reaction can be calculated by using Hess's law:

The law states that 'the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps'.

[2] - 2 × [1] = [3]

$O_2+4HI\rightarrow 2H_2O(g)+2I_2(s)$

$\Delta H^{o}_{3}=\Delta H^{o}_{2}-2\times \Delta H^{o}_{1}$

$=-483.64 kJ/mol - 2\times (52.96 kJ/mol)=-586.56 kJ/mol$

The standard enthalpy of the 3rd reaction is -586.56 kJ/mol.The negative sign indicates that energy is released during this reaction.

6 0

3 years ago

In general, what makes one kind of amino acid different from other amino acids?

Vinvika [58]

There is part of an amino acid molecule that is called the R group or side chain. The side chain of the amino acid called glycine is a single hydrogen atom. The side chain is what differs from amino acid to amino acid.

5 0

3 years ago

How are chemicals used in gasoline?

timofeeve [1]

Answer:A typical gasoline mixture contains about 150 different hydrocarbons, including butane, pentane, isopentane and the BTEX compounds (benzene, ethylbenzene, toluene, and xylenes). Gasoline also contains chemicals such as lubricants, anti-rust agents and anti-icing agents that are added to improve car performance.

5 0

3 years ago

Suppose a 500.mL flask is filled with 1.0mol of CO, 1.5mol of H2O and 0.70mol of CO2. The following reaction becomes possible: +

valentina_108 [34]

Answer:

[CO] = 0.62 M

Explanation:

Step 1: Data given

Volume of the flask = 500 mL

Number of moles CO = 1.0 moles

Number of moles H2O = 1.5 moles

Number of moles CO2 = 0.70 moles

The equilibrium constant K for this reaction is 3.80

Step 2: The balanced equation

CO(g) + H2O(g) ⇆ CO2(g) +H2(g)

Step 3: Calculate the initial concentrations

Concentration = moles / volume

[CO] = 1.0 moles / 0.500 L = 2.0 M

[H2O] = 1.5 moles / 0.500 L = 3.0 M

[CO2] = 0.70 moles / 0.500 L = 1.4 M

[H2] = 0M

Step 4: The concentration at the equilibrium

For 1 mol CO we have 1 mol H2O to produce 1 mol CO2 and 1 mol H2

[CO] = 2.0 -X M

[H2O] = 3.0 - X M

[CO2] =1.4 + X M

[H2] = X M

Step 5: Define Kc

Kc = [CO2][H2]/ [CO][H2O]

3.80 = (1.4 + X) * X / ((2.0 - X)*3.0 -X))

X = 1.38

[CO] = 2.0 -1.38 = 0.62 M

[H2O] = 3.0 - 1.38 = 1.62 M

[CO2] =1.4 + 1.38 M = 2.78

[H2] = 1.38 M

Kc = (2.78*1.38) / (0.62*1.62)

Kc = 3.8

[CO] = 0.62 M

8 0

3 years ago

Pls help me I have 5 mins Science is a unique field of thought because it relies on _______ to describe the world

Pani-rosa [81]

Most reasonable answer:
Observations and experimentation

5 0

3 years ago