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Harman [31]
3 years ago
8

PLEASE HELP ME

Chemistry
1 answer:
vichka [17]3 years ago
4 0
Light moves in a straight line except at surfaces between different transparent materials, where its path bends.
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What’s the two products of H2Co3
forsale [732]

Answer:

Hydrogen and Cobalt

Explanation:

Break up each individual element

- Hope that helps! Please let me know if you need further explanation.

6 0
3 years ago
Hydrogen is a reactive gas under normal conditions.Based on this property alone, to which group of the periodic table should hyd
denis23 [38]
Even though Hydrogen is originally in group 1, based on this property, we can say it is in group 6.

Because:

Group 6 would mean that it only needs 2 more valence electrons till the octet (8 valence electrons). This would make it reactive, yet, in normal conditions, unlike group 7.
5 0
3 years ago
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Pls Help!!!!! ASAP!!!!​
HACTEHA [7]

Answer:

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Explanation:

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7 0
2 years ago
Can you Convert 75°F to °C
Leya [2.2K]

Answer: 23.8889

Explanation:

(75°F − 32) × 5/9 = 23.889°C

5 0
3 years ago
A chemistry student is given 600. mL of a clear aqueous solution at 37.° C. He is told an unknown amount of a certain compound X
barxatty [35]

Answer:

  • <u>Yes, it is 14. g of compound X in 100 ml of solution.</u>

Explanation:

The relevant fact here is:

  • the whole amount of solute disolved at 21°C is the same amount of precipitate after washing and drying the remaining liquid solution: the amount of solute before cooling the solution to 21°C is not needed, since it is soluble at 37°C but not soluble at 21°C.

That means that the precipitate that was thrown away, before evaporating the remaining liquid solution under vacuum, does not count; you must only use the amount of solute that was dissolved after cooling the solution to 21°C.

Then, the amount of solute dissolved in the 600 ml solution at 21°C is the weighed precipitate: 0.084 kg = 84 g.

With that, the solubility can be calculated from the followiing proportion:

  • 84. g solute / 600 ml solution = y / 100 ml solution

      ⇒ y = 84. g solute × 100 ml solution / 600 ml solution = 14. g.

The correct number of significant figures is 2, since the mass 0.084 kg contains two significant figures.

<u>The answer is 14. g of solute per 100 ml of solution.</u>

7 0
2 years ago
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