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3 years ago

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PLEASE HELP ME

1 answer:

vichka [17]3 years ago

4 0

Light moves in a straight line except at surfaces between different transparent materials, where its path bends.

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Which example is a homogenous mixture of two or more pure substances? alcohol

il63 [147K]

Answer:

Alcohol and water.

Explanation:

Alcohol and water is a homogenous mixture. because these two liquids are soluble, miscible in all composition. A homogenous mixture is a solution that has equal composition of its components.

Irregular mixing of two liquid components have different refractive indexes. At a high temperature, it can become inhomogenous spontaneously.

A solution is a type of homogenous mixture which composed of two or more substances. In a mixture a solute is a substance, dissolves in other substance that is solvents like alcohol and water, alcohol is solute and water is a solvent.

6 0

3 years ago

A. Based on the activation energies and frequency factors, rank the following reactions from fastest to slowest reaction rate, a

deff fn [24]

Answer:

A) $E_{a} = 350KJ/mol$ , $E_{a} = 50KJ/mol$ , $E_{a} = 50KJ/mol$

A = 1.5× $10^{-7}s^{-1}$ , A = 1.9× $10^{-7} s^{-1}$ , A=1.5× $10^{-7} s^{-1}$

B) 4.469

Explanation:

From Arrhenius equation

$K=Ae^{\frac{E_{a} }{RT} }$

where; K = Rate of constant

A = Pre exponetial factor

$E_{a}$ = Activation Energy

R = Universal constant

T = Temperature in Kelvin

Given parameters:

$E_{a} =165KJ/mol$

$T_{1}=505K$

$T_{2}=525K$

$R=8.314JK^{-1}mol^{-1}$

taking logarithm on both sides of the equation we have;

$InK=InA-\frac{E_{a} }{RT}$

since we have the rate of two different temperature the equation can be derived as:

$In(\frac{K_{2} }{K_{1} } )=\frac{E_{a} }{R}(\frac{1}{T_{1} } -\frac{1}{T_{2} } )$

$In(\frac{K_{2} }{K_{1} } )=\frac{165000J/mol}{8.314JK^{-1}mol^{-1} }.(\frac{1}{505} -\frac{1}{525} )$

$In(\frac{K_{2} }{K_{1} } )$ = 19846.04×7.544× $10^{-5}$ = 1.497

$\frac{K_{2} }{K_{1} }$ = $e^{1.497}$ = 4.469

6 0

3 years ago

With white light, a team measured a 0.7% percent change with 3.5g of plant matter in a one liter container. Convert

Strike441 [17]

moles CO₂ = 5.57.10⁻⁴

<h3>Further explanation </h3>

A mole is a number of particles(atoms, molecules, ions) in a substance

Can be formulated :

$\tt mol=\dfrac{mass}{MW}$

0.7% percent change with 3.5g of plant matter

mass :

$\tt 0.7\%\times 3.5~g=0.0245~g$

moles :

$\tt moles=\dfrac{0.0245}{44}=0.000557=5.57.10^{-4}$

5 0

3 years ago

Making models involves creating representations of complex objects or processes to help people study and understand things that

swat32

Somewhat false
observations can be made of a model of the statue of liberty, say, or in real line

6 0

3 years ago

What is the volume when the density is 7.83g/ml and 19.6 grams?

insens350 [35]

To fine volume, you have to divide the mass by the density of the substance. in this, you’ll do 19.6/7.83=2.50

4 0

3 years ago