1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brrunno [24]
3 years ago
13

As members approach the ending of a group or are leaving an ongoing group, it is equally essential that they be encouraged to ex

press their reactions. They may have fears or concerns about __________. a. cohesion​ b. ​separation c. ​connection d. ​bonding
Chemistry
1 answer:
34kurt3 years ago
7 0

Answer:

The answer is A. Cohesion

Explanation:

The reason is for them to be able to stick together.

You might be interested in
Earth is currently 150 million km away from the Sun. If Earth was 200 million km away from the Sun, why would it no longer be ab
timurjin [86]

Answer:

The temperature would be too cold

Explanation:

4 0
3 years ago
Why is heat needed to get a reaction to occur
Ahat [919]

Answer:As temperature increases, reactions take place. Generally, higher temperatures mean faster reaction rates; as molecules move about more quickly, reactant molecules are more likely to interact, forming products.

Explanation:

4 0
3 years ago
Read 2 more answers
Dermal tissue in plants, is most like what tissue in humans?
Arte-miy333 [17]
The dermal tissue is basically the outer part of the cell that protects the plant cell so in that case it would be the carbohydrate or cell wall. If you would put the choices it could have been a bit better :)
7 0
3 years ago
Joan’s initial nickel (II) chloride sample was green and weighed 4.3872 g. After the dehydration reaction and removal of excess
ANEK [815]

Answer:

a) yes, it was an hydrate

b) the number of waters of hydration, x = 6

Explanation:

a) yes it was an hydrate because the mass decreased after the process of dehydration which means removal of water thus some water molecules were present in the sample.

b) NiCl2. xH2O

mass if dehydrated NiCl2 = 2.3921 grams

mass of water in the hydrated sample = mass of hydrated - mass of dehydrated = 4.3872 - 2.3921 = 1.9951 g which represent the mass of water that was present in the hydrated sample.

NiCl2.xH2O

mole of dehydrated NiCl2 = m/Mm = 2.3921/129.5994 = 0.01846 mole

mole of water = m/Mm = 1.9951/18.02 = 0.11072 mole

Divide both by the smallest number of mole (which is for NiCl2) to find the coefficient of each

for NiCl2 = 0.01846/0.01846 = 1

for H2O = 0.11072/0.01846 = 5.9976 = 6

thus the hydrated sample was NiCl2. 6H2O

4 0
3 years ago
You burn a 15g jellybean to warm 50 mL of water, which increases the temperature of the water 25 °C. How many calories of heat a
Juli2301 [7.4K]

Answer:

Q = 375\,cal

Explanation:

The quantity of heat transfered from the jellybean to the water is:

Q = \rho\cdot V \cdot c\cdot \Delta T

Q = \left(1\,\frac{g}{cm^{3}}\right)\cdot (15\,cm^{3})\cdot \left(1\,\frac{cal}{g\cdot ^{\circ} C} \right)\cdot (25\,^{\circ}C )

Q = 375\,cal

7 0
3 years ago
Read 2 more answers
Other questions:
  • If a solution is considered basic, then _____________
    9·1 answer
  • What element is not classified as a metal, nonmetal, or metalloid?​
    14·1 answer
  • What is the total concentration of ions in a 0.10 M solution of barium chloride?
    9·2 answers
  • (20 Points)
    6·2 answers
  • Valerie wants to examine the properties of a thick liquid but is finding it difficult to pour the liquid into a beaker. She need
    9·1 answer
  • What are the rules for calculating protons
    5·1 answer
  • 60<br> х<br> 8<br> у<br> x=<br> 04<br> 09<br> O 16
    10·1 answer
  • A student dissolved 3.50g of copper (II) nitrate in water and mixed it with a solution of sodium carbonate. The student recovere
    9·1 answer
  • Which best describes how food availability affects the carrying capacity of an area
    9·1 answer
  • Fe3+ and S2- write the formula for the compound that would be formed
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!