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stealth61 [152]
3 years ago
13

In humans, the allele for curly hair and the allele for straight hair show incomplete dominance the offspring of a curly haired

person and a straight haired person will have A) Curly hair B) straight hair C) wavy hair D) Curly and straight hair
Chemistry
2 answers:
Alex17521 [72]3 years ago
7 0

Answer:

A

Explanation:

Curly Hair

Vika [28.1K]3 years ago
3 0
A
eplanation
i meannn they both had curly hair
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PLS HELP 6TH GRADE ITS ONE QUESTION ABOUT SCIENCE
julia-pushkina [17]

Answer: The answer is C

Explanation:

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3 years ago
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What volume of chlorine gas (Cl2), measured at STP, can be produced by the decomposition of 73.0g of hydrogen chloride gas (HCl)
gayaneshka [121]

Answer:

Explanation:

2HCl    =   H₂   +   Cl₂

2 mole     1 mole      1 mole

73 gram HCl = 73 / 36.5 = 2 mole of HCl

2 moles of HCl will produce 1 mole of chlorine gas .

At STP , one mole of chlorine gas has volume equal to 22.4 litre .

8 0
3 years ago
What volume of carbon dioxide, at 1 atm pressure and 112°C, will be produced when 80.0 grams of methane is burned?
Vadim26 [7]

Answer:

158 L.

Explanation:

What is given?

Pressure (P) = 1 atm.

Temperature (T) = 112 °C + 273 = 385 K.

Mass of methane CH4 (g) = 80.0 g.

Molar mass of methane CH4 = 16 g/mol.

R constant = 0.0821 L*atm/mol*K.

What do we need? Volume (V).

Step-by-step solution:

To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:

PV=nRT.

Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.

So, let's find the number of moles that are in 80.0 g of methane using its molar mass. This conversion is:

80.0g\text{ CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5\text{ moles CH}_4.

So, in this case, n=5.

Now, let's solve for 'V' and replace the given values in the ideal gas law equation:

V=\frac{nRT}{P}=\frac{5\text{ moles }\cdot0.0821\frac{L\cdot atm}{mol\cdot K}\cdot385K}{1\text{ atm}}=158.04\text{ L}\approx158\text{ L.}

The volume would be 158 L.

6 0
1 year ago
Ozone (O 3) is made of three atoms of oxygen. It is _
kykrilka [37]
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3 0
3 years ago
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Arbon dioxide is dissolved in blood (ph 7.5) to form a mixture of carbonic acid and bicarbonate. Part a neglecting free co2, wha
Aleks04 [339]

Answer : The fraction of carbonic acid present in the blood is 5.95%

Explanation :

The mixture consists of carbonic acid ( H₂CO₃) and bicarbonate ion ( HCO₃⁻). This represents a mixture of weak acid and its conjugate which is a buffer.

The pH of a buffer is calculated using Henderson equation which is given below.

pH = pKa + log \frac{[Base]}{[Acid]}

We have been given,

pH = 7.5

pKa of carbonic acid = 6.3

Let us plug in the values in Henderson equation to find the ratio Base/Acid.

7.5 = 6.3 + log \frac{[base]}{[acid]}

1.2 = log \frac{[base]}{[acid]}

\frac{[Base]}{[Acid]} = 10^{1.2}

\frac{[Base]}{[Acid]} = 15.8

[Base] = 15.8 \times [Acid]

The total of mole fraction of acid and base is 1. Therefore we have,

[Acid] + [Base] = 1

But Base = 15.8 x [Acid]. Let us plug in this value in above equation.

[Acid] + 15.8 \times [Acid] = 1

16.8 [Acid] = 1

[Acid] = \frac{1}{16.8}

[Acid] = 0.0595

[Acid] = 0.0595 x 100 = 5.95 %

The fraction of carbonic acid present in the blood is 5.95%

4 0
3 years ago
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