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3 years ago

How many minutes are in 230 seconds?

Chemistry

2 answers:

DIA [1.3K]3 years ago

8 0

Answer:

230 Seconds = 3.83333333 Minutes

Explanation:

AlexFokin [52]3 years ago

7 0

Answer:

3 minutes and 50 seconds

Explanation:

If there are 60 seconds in 1 minute..

60, 120, 180 (1 minute, 2 minutes, 3 minutes)

230 - 180 = 50

So it's 230 seconds consists of 3 minutes and 50 seconds.

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Use the mass and volume data to calculate the density of mercury to the nearest tenth. Mass of mercury = 57 g Volume of mercury

Elena-2011 [213]

Density = mass/volume = 57g/4.2 mL ≈ 13.6 g/mL

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4 years ago

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Type the correct answer in the box. Given: SiO2 4HF → SiF4 2H2O In this chemical reaction, how many grams of HF are needed for 1

Tresset [83]

The mass of the substance is the product of the molar mass and the moles of the substance in the compound. The amount of the HF required in the reaction is 242 gm.

<h3>What is the relation of the mass and moles?</h3>

Mass is given as the product of the moles of the substance and of the molar mass of the substance in the compound.

Given,

Molar mass of Silicon dioxide = 60g/mol

mass of Silicon dioxide = 182 g

Molar mass of HF = 20 g/mol

Moles of the Silicon dioxide can be calculated as,

$\begin{aligned}\rm Moles &= \rm \dfrac{mass}{molar\;mass}\\\\&= {182}{60}\\\\&= 3.03\end{aligned}$

The balanced chemical reaction can be shown as,

$\rm SiO_{2} + 4HF \rightarrow SiF_{4} + 2H_{2}O$

From the reaction, it can deduce that,

1 mole of silicon dioxide reacts with 4 moles of HF

So, 3.03 moles of silicon dioxide reacts with 12.12 moles of HF

Mass of HF can be calculated as,

$\begin{aligned}\text{mass of HF} &= \rm moles \times \rm molar \; mass\\\\&= 12.12 \times 20\\\\&= 242 \;\rm g\end{aligned}$

Therefore, the reaction requires 242 gm of HF.

Learn more about mass here:

brainly.com/question/11558651

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2 years ago

Write the equation that shows how phosphate ions react with calcium ions in hard water to form an insoluble precipitate.

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6Ca 2+ + 4PO4 3+ -----> 2Ca3(PO4)2

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4 years ago

What is the value of log 43? Use the calculator. Round your answer to the nearest tenth.

ZanzabumX [31]

Answer:

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Explanation:

log 43 = 1.6335

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3 years ago

When 25.0 mL of a solution of 1.4 x 10-3 M silver nitrate is mixed with 60.0 mL of a solution of 7.5 x 10-4 M sodium chloride a)

LUCKY_DIMON [66]

Step one write the equation for dissociation of AgNO3 and NaCl

that is AgNO3-------> Ag+ + NO3-

NaCl--------> Na+ + Cl-
then find the number of moles of each compound
that is for AgNO3 = ( 1.4 x10^-3 ) x 25/1000= 3.5 x10^-5 moles
Nacl= (7.5 x10^-4)x 60/1000= 4.5 x10^-5 moles

from mole ratio the moles of Ag+= 3.5 x10^-5 moles and that of Cl-= 4.5 x10^-4 moles

then find the total volume of the mixture
that is 25ml + 60 Ml =85ml = 0.085 liters

The Ksp of Agcl = (Ag+) (cl-), let the concentration of Ag+ be represented by x and also the concentration be represented by x

ksp (1.8 x10^-10) is therefore= x^2

find the square root x=1.342 x10^-5

Ag+ in final mixture is = moles of Ag+/total volume - x
that is {(3.5 x10^-5)/0.085} - 1.342 x10^-5=3.98x10^-4

Cl- in the final mixture is =(4.5 x10^-5 /0.085) - 1.342 x10^-5= 5.16 x10^-4

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4 years ago

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