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Bond [772]
3 years ago
13

The decomposition of 57.0 g of Fe2O3 results in Consider the following reaction. 2Fe2O3 ---> 4Fe + 3O2 deltaH degree rxn = +

824.2 kJ decomposition of 57.0 g of Fe2O3 results in the release of 294 kJ of heat. A. the absorption of 23500 kJ of heat. B. the absorption of 147 kJ of heat. C. the absorption of 294 kJ of heat. D. the release of 23500 kJ of heat. E. the release of 147 kJ of heat.
Chemistry
1 answer:
lozanna [386]3 years ago
3 0

Answer:

The correct answer is option E.

Explanation:

2Fe_2O_3\rightarrow 4Fe + 3O_2 \Delta H^o_{rxn} = 824.2 kJ

Mass of ferric oxide decomposed = 57.0 g

Moles of ferric oxide decomposed = \frac{57.0 g}{160 g/mol}=0.35625 mol

According to reaction, 2 moles ferric oxide on combustion gives 824.2 kJ of heat.

Then heat given by on decomposition of 0.35625 mol of ferric oxide will be:

\frac{824.2 kJ}{2}\times 0.35625 =146.81 kJ\approx 147 kJ

So, on decomposition of 57.0 grams of ferric oxide 147 kilo Joules of heat was released.

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Answer:

Explanation:

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8 0
3 years ago
Read 2 more answers
CaC2 + 2H2O ➞ C2H2 + Ca(OH)2
Paraphin [41]

Answer:

A. 0.5 mole of Ca(OH)₂.

B. 4.37 moles of H₂O.

Explanation:

The balanced equation for the reaction is given below:

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

Next, we shall determine the mass of CaC₂ that reacted and the mass of C₂H₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of CaC₂ = 40 + (12×2)

= 40 + 24

= 64 g/mol

Mass of CaC₂ from the balanced equation = 1 × 64 = 64 g

Molar mass of C₂H₂ = (12×2) + (2×1)

= 24 + 2

= 26 g/mol

Mass of C₂H₂ from the balanced equation = 1 × 26 = 26 g

SUMMARY:

From the balanced equation above,

64 g of CaC₂ reacted with 2 moles of H₂O to produce 26 g of C₂H₂ and 1 mole of Ca(OH)₂.

A. Determination of the number of mole of Ca(OH)₂ produced by the reaction of 32.0 g of CaC₂.

From the balanced equation above,

64 g of CaC₂ reacted to produce 1 mole of Ca(OH)₂.

Therefore, 32 g of CaC₂ will react to produce = (32 × 1)/64 = 0.5 mole of Ca(OH)₂.

Thus, 0.5 mole of Ca(OH)₂ were obtained from the reaction.

B. Determination of the number of mole of H₂O needed to produce 56.8 g C₂H₂.

From the balanced equation above,

2 moles of H₂O reacted to produce 26 g of C₂H₂.

Therefore, Xmol of H₂O will react to produce 56.8 g C₂H₂ i.e

Xmol of H₂O = (2 × 56.8)/26

Xmol of H₂O = 4.37 moles

Thus, 4.37 moles of H₂O is needed for the reaction.

3 0
3 years ago
**MEDAL AND FAN** what structural units make up metallic solids?
Margarita [4]
C)

Metallic solids consist of metal ions which are surrounded by delocalized electrons.
8 0
3 years ago
2Al(s) + Fe2O3(s) → Al2O3(s) + 2Fe(s) T
brilliants [131]

Answer:

ΔHrxn = [(1) -1675.5 ( kJ/mole) + (2) 0 ( kJ/mole)] - [(1) -824.3 ( kJ/mole) + (2) 0 ( kJ/mole)]

Explanation:

ΔHrxn = 2ΔHf (Al₂O₃)  - ΔHf (Fe₂O₃)

Remember that for pure elements in their standard state of temperature and pressure by definition their standard heats of formation are zero.

ΔHrxn = 2(-1675.7) - (-824.3) kJ/mol

ΔHrxn = 2527 kJ/mol

6 0
3 years ago
I need answers to question 1,2,3
sashaice [31]

Answer:

1. 0.125 mole

2. 42.5 g

3. 0.61 mole

Explanation:

1. Determination of the number of mole of NaOH.

Mass of NaOH = 5 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mole of NaOH =?

Mole = mass /molar mass

Mole of NaOH = 5/40

Mole NaOH = 0.125 mole

2. Determination of the mass of NH₃.

Mole of NH₃ = 2.5 moles

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 2.5 × 17

Mass of NH₃ = 42.5 g

3. Determination of the number of mole of Ca(NO₃)₂.

Mass of Ca(NO₃)₂ = 100 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]

= 40 + 2[14 + 48]

= 40 + 2[62]

= 40 + 124

= 164 g/mol

Mole of Ca(NO₃)₂ =?

Mole = mass /molar mass

Mole of Ca(NO₃)₂ = 100 / 164

Mole of Ca(NO₃)₂ = 0.61 mole

6 0
3 years ago
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