Question

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.44 m/s, and an 64.8-kg person feels a 261-N force pressing against his back. What is the radius of a chamber?

Answer 1

Answer:

r = 2.93 m

Explanation:

mass of the person = 64.8 kg

speed v = 3.44 m/s                  

Force F = 261 N

using formula                        

$F = \dfrac{mv^2}{r}$

the radius of the chamber is given by

$r = \dfrac{mv^2}{F}$                  

$r = \dfrac{64.8\times 3.44^2}{261}$

r = 2.93 m                                      

so, the radius of a chamber is equal to 2.93 m