Answer:
Mc = 900 Kg
Uc = 28 ms^-1
Md = 70 Kg
Ud = 0
We want Vd
Vc = Vd
This situation is elastic momentum
Answer:
Make Brilliant
Explanation:
Answer the following questions on the basis of given ray diagram.
1. Name the rays A and B.
2. Which ray has more speed ( A or B ) in the glass medium ?
3. Which phenomenon is shown in the given diagram ?
4. Ray B is bending more than the ray A. What is the reason behind it ?
Answer:
Explanation:
Given that,
Radius r = 15cm = 0.15m
Area of the circular loop can be determined using the formula for area of a circle
A = π r²
A = π × 0.15²
A = 0.0708 m²
Magnetic field B = 1.2T in positive z direction
B = 1.2 •k T.
If loop is remove from the field in the time interval
∆t = 2.3ms = 2.3×10^-3s
We want to find the average EMF and it is given as
ε = —∆Φ/∆t
The final flux is zero
Φf = 0
Where magnetic flux is given as
Φi = BA Cosθ
Where θ=0 since the area and the magnetic field point in the same direction.
Φi = BA Cos0
Φi = BA
Φi = 1.2 × 0.0708
Φi = 0.0848 Vs
Then, ε = —∆Φ/∆t
ε = —(Φf — Φi) / ∆t
ε = —(0-0.0848) / (2.3×10^-3)
ε = 0.0848 / (2.3×10^-3)
ε = 36.88 V
The EMF is 36.88 Volts
Answer:
Explanation:
a )
The Gaussian surface must have contained both the charges like +3 nC and - 3 nC , total charges being zero . According the Gauss's law , total electric flux over a closed surface is equal to 1 / ε₀ times the total charge contained inside the closed surface .
Since total charge inside is zero , total flux will be 1 / ε₀ x 0 = 0
b )
In this case the Gaussian surface is so small that it contains only the charge
+ 3 nC .
So electric flux over the Gaussian surface
= ( 1 / ε₀ ) x 3 x 10⁻⁹
= (1 / 8.85 x 10⁻¹² ) x 3 x 10⁻⁹
= 3 x 10³ / 8.85
= 339 weber.
=
