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kap26 [50]
3 years ago
14

A tub of water is placed in a small room and heat is removed from the room. What will most likely occur if enough heat is remove

d? (A)The water will freeze. (B)The water will evaporate. (C)The water will become a gas. (D)The water will change from gas to solid
Physics
2 answers:
frez [133]3 years ago
8 0

Answer:

A. the water will freeze.

Explanation:

the water is initially liquid because the particles have energy which causes movement which gives off heat. if heat (energy) is removed from the room, the waters energy will radiate outward and dissipate taking the energy away from the water causing it to freeze

NARA [144]3 years ago
6 0

Answer:

(A)The water will freeze.

Explanation:

Heat is the energy that when transferred causes change in temperature. If heat is added to a body by some process the bodies temperature increases and if heat is removed from a body by some process the temperature reduces.

In this case if enough heat is removed from the room the internal movement of the water particles will slow down causing the water to form crystal lattice thus forming ice. So, the water will freeze.

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A 1.75 kg stone falls from the top of a cliff and strikes the ground at a speed of 58.8 m/s. What is the height of the cliff??
Reil [10]

Answer:

172.9m

Explanation:

h = 1/2 gt^

First calculat for t using

v = gt

t = v/g = 58.8/10

= 5.88secs

now h = 1/2 x 10 x 5.88^2

h =1/2 x 10 x 34.57

= 345.74/2

= 172.9m

6 0
4 years ago
A particle (charge = 40 μC) moves directly toward a second particle (charge = 80 μC) which is held in a fixed position. At an in
lisov135 [29]

Answer:

The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m

Explanation:

Given that,

First charge = 40 μC

Second charge = 80 μC

Distance between the two particles = 2.0 m

Kinetic energy = 16 J

We need to calculate the distance separating the two particles when the moving particle is momentarily stopped

Using conservation of energy

K.E+\dfrac{kq_{1}q_{2}}{d}=\dfrac{kq_{1}q_{2}}{x}+K.E

Put the value into the formula

16+\dfrac{9\times10^{9}\times40\times10^{-6}\times80\times10^{-6}}{2}=\dfrac{9\times10^{9}\times40\times10^{-6}\times80\times10^{-6}}{x}+0

16+14.4=\dfrac{28.8}{x}

30.4x=28.8

x=\dfrac{28.8}{30.4}

x=0.947\ m

Hence, The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m

8 0
3 years ago
A rod made up of certaon metall which had coefficiebt of volume expansion is 33×10^-6 per celsius degrer.The rod is 100 meter lo
Irina-Kira [14]

Answer:

100.11 m

Explanation:

Given:

Coefficient of volume expansion, \alpha_{v}=33\times10^{-6} /°C.

Initial length of rod, l=100 m

Change in temperature, ΔT=(90-(-10))=100 °C

We know that,

\alpha_{v}=3\alpha_{L}\\\alpha_{L}=\frac{\alpha_{v}}{3}\\\alpha_{L}=\frac{33\times10^{-6}}{3}=11\times10^{-6} /°C

Here, \alpha_{L} is the coefficient of linear expansion.

Now, we know that,

Change in length (Δl) is given as,

\Delta l=\alpha_L\times L\times\Delta T

Plug in all the values and solve for l.

This gives,

\Delta l=11\times10^{-6}\times 100\times100\\\Delta l=0.11 \textrm{ m}

Therefore, the length of rod after expansion is L+\Delta l=100+0.11=100.11 m.

4 0
3 years ago
If the kinetic and potential energy in a system are equal, then the potential energy increases. What happens as a result? Total
nexus9112 [7]
Energy of motion decreases
4 0
3 years ago
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