You'd do 10x320/34 because that's how you find velocity.
Answer:
See answer
Explanation:
The area of the circular loop is given by:
![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20r%5E2)
The magnetic flux is given by:
![\phi = \int \vec{B} \cdot d\vec{A}](https://tex.z-dn.net/?f=%5Cphi%20%3D%20%5Cint%20%5Cvec%7BB%7D%20%5Ccdot%20d%5Cvec%7BA%7D)
is parallel to
and
is constant in magnitude and direction therefore:
![\phi = \int \vec{B} \cdot d\vec{A}= \int BdAcos(0)= B\int dA= B*(\pi r^2)= \pi Br^2](https://tex.z-dn.net/?f=%5Cphi%20%3D%20%5Cint%20%5Cvec%7BB%7D%20%5Ccdot%20d%5Cvec%7BA%7D%3D%20%5Cint%20BdAcos%280%29%3D%20B%5Cint%20dA%3D%20B%2A%28%5Cpi%20r%5E2%29%3D%20%5Cpi%20Br%5E2)
Part A)
initially the flux is ![\phi =\pi B r^2](https://tex.z-dn.net/?f=%5Cphi%20%3D%5Cpi%20B%20r%5E2)
after the interval
the flux is
![\phi = 0](https://tex.z-dn.net/?f=%5Cphi%20%3D%200)
now, the EMF is defined as:
,
if we consider
very small then we can re-write it as:
![\epsilon =- \frac{\Delta \phi}{\Delta t}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D-%20%5Cfrac%7B%5CDelta%20%5Cphi%7D%7B%5CDelta%20t%7D)
then:
![\epsilon =- \frac{-0.12}{0.0024} = 50 [V]](https://tex.z-dn.net/?f=%5Cepsilon%20%3D-%20%5Cfrac%7B-0.12%7D%7B0.0024%7D%20%3D%2050%20%5BV%5D)
Part B)
When looked down from above, the current flows counter clockwise, according to the right hand rule, if you place your thumb upwards (the direction of the magnetic field) and close your fingers, then the current will flow in the direction of your fingers.
Answer:
r² / 110² − 3z² / 1375² = 1
Explanation:
The equation of a hyperboloid (which is a hyperbola rotated about the z axis or conjugate axis) that is centered at the origin is:
x² / a² + y² / b² − z² / c² = 1
If the cross sections are circular rather than elliptical, then a = b.
(x² + y²) / a² − z² / c² = 1
Or, if you prefer cylindrical coordinates:
r² / a² − z² / c² = 1
We know that at z = 0, r = 110. And at z = -500, r = 130.
110² / a² − 0 = 1
130² / a² − (-500)² / c² = 1
Solving:
a² = 110²
c² = 1375² / 3
Plugging in:
r² / 110² − 3z² / 1375² = 1
The interior part of Jupiter and Saturn are different from each other due to difference of core and magnetic field.
<h3>How do the interiors of Jupiter and Saturn differ? </h3>
The interiors of Jupiter and Saturn differ from one another because Jupiter has a larger metallic hydrogen core as compared to Saturn. It has stronger magnetic field as compared to Saturn.
So we can conclude that the interior part of Jupiter and Saturn are different from each other due to difference of core and magnetic field.
Learn more about Jupiter here: brainly.com/question/3522722
#SPJ11
Yes; form the outermost layer it goes: exosphere, thermosphere, mesosphere, stratosphere, and troposphere(the troposphere is where we live).