Answer:
172.9m
Explanation:
h = 1/2 gt^
First calculat for t using
v = gt
t = v/g = 58.8/10
= 5.88secs
now h = 1/2 x 10 x 5.88^2
h =1/2 x 10 x 34.57
= 345.74/2
= 172.9m
Answer:
The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m
Explanation:
Given that,
First charge = 40 μC
Second charge = 80 μC
Distance between the two particles = 2.0 m
Kinetic energy = 16 J
We need to calculate the distance separating the two particles when the moving particle is momentarily stopped
Using conservation of energy

Put the value into the formula





Hence, The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m
Answer:
100.11 m
Explanation:
Given:
Coefficient of volume expansion,
/°C.
Initial length of rod, 
Change in temperature, ΔT=
°C
We know that,
/°C
Here,
is the coefficient of linear expansion.
Now, we know that,
Change in length (Δl) is given as,

Plug in all the values and solve for
.
This gives,
Therefore, the length of rod after expansion is
m.
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