Answer:
Option C. 5,000 kg m/s
Explanation:
<u>Linear Momentum on a System of Particles
</u>
Is defined as the sum of the momenta of each particles in a determined moment. The individual momentum is the product of the mass of the particle by its speed
P=mv
The question refers to an 100 kg object traveling at 50 m/s who collides with another object of 50 kg object initially at rest. We compute the moments of each object


The sum of the momenta of both objects prior to the collision is


1)
p = 2.4 * 10^5 Pa
T = 18° C + 273.15 = 291.15 k
r = 0.25 m => V = [4/3]π(r^3) = [4/3]π(0.25m)^3 = 0.06545 m^3 = 65.45 L
Use ideal gas equation: pV = nRT => n = pV / RT = [2.4*10^5 Pa * 0.06545 m^3] / [8.31 J/k*mol * 291.15k] = 6.492 mol
Avogadro number = 1 mol = 6.022 * 10^23 atoms
Number of atoms = 6.492 mol * 6.022 *10^23 atom/mol = 39.097 * 10^23 atoms = 3.91 * 10^24 atoms
2) Double atoms => double volume
V2 / V1 = r2 ^3 / r1/3
2 = r2 ^3 / r1 ^3 => r2 ^3 = 2* r1 ^3
r2 = [∛2]r1
The factor is ∛2
Answer:

Explanation:
In this question we have given
mass of airplane=.6 Kg
Radius of horizontal circle,r=6m
Time taken to complete 1.6 revolution=5s
Therefore time taken to complete 1 revolution, t=
t=3.1 s
We have to find the speed of airplane
We will first find the distance covered by airplane in tracing one circle which is equal to circumference of circle
We know that
Circumference,d = 
or 

We know that speed=
............(1)
Put value of d and t in equation 1
speed=

Answer:
B
Explanation:
to see how fast she is going per second, you would have to divide the distance traveled by the seconds it took to travel the distance