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steposvetlana [31]
3 years ago
6

A juggler throws a ball straight up into the air. The ball remains in the air for a time (t) before it lands back in the juggler

s hand. What is the acceleration of the ball during the entire time the ball is in the air?
Physics
1 answer:
natka813 [3]3 years ago
5 0

Answer:

9.8 m/s^2, downward

Explanation:

There is only one force acting on the ball during its motion: the force of gravity, which is given by

F=mg

where

m is the mass of the ball

g=9.8 m/s^2 is the acceleration of gravity (downward)

According to Newton's second law,

F=ma

where F is the net force on the object and a is its acceleration. Rearranging for a,

a=\frac{F}{m}

As we said, the only force acting on the ball is gravity, so F = mg and the acceleration of the ball is:

a=\frac{mg}{m}=g

Therefore, the ball has a constant acceleration of 9.8 m/s^2 downward for the entire motion.

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Explanation:

Given that,

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The acceleration due to gravity at the surface of the moon is 1.62 m/s².

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h'=ut-\dfrac{1}{2}gt^2\\\\h'=30\times 30.86-\dfrac{1}{2}\times 1.62\times 30.86^2\\\\h'=154.40\ m

or

h' = 155 m

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