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RSB [31]
3 years ago
10

What is meant by cathode rays?what is radio activity and state three of it's effects?​

Physics
1 answer:
stealth61 [152]3 years ago
5 0

1cathode rays plural : the high-speed electrons emitted in a stream from the heated cathode of a vacuum tube

2: a stream of electrons emitted from the cathode of a vacuum tube —usually used in plural

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Use the image to determine the volume of the rock.
maria [59]

Answer:

12 ml

Explanation:

The initial volume in the cylinder is 20 ml

 adding the rock adds volume to the cylinder

       the new volume is 32 ml .....the increase in volume is the volume of the rock :   32 - 20 = 12 ml    volume of rock

6 0
1 year ago
A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the
Margaret [11]

Hi there!

\boxed{\omega = 0.38 rad/sec}

We can use the conservation of angular momentum to solve.

\large\boxed{L_i = L_f}

Recall the equation for angular momentum:

L = I\omega

We can begin by writing out the scenario as a conservation of angular momentum:

I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)

I_m = moment of inertia of the merry-go-round (kgm²)

\omega_m = angular velocity of merry go round (rad/sec)

\omega_f = final angular velocity of COMBINED objects (rad/sec)

I_b = moment of inertia of boy (kgm²)

\omega_b= angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

I = MR^2

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

\omega = \frac{v}{r}

L_b = MR^2(\frac{v}{R}) = MRv

Plug in the given values:

L_b = (20)(3)(5) = 300 kgm^2/s

Now, we must solve for the boy's moment of inertia:

I = MR^2\\I = 20(3^2) = 180 kgm^2

Use the above equation for conservation of momentum:

600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}

8 0
2 years ago
If the mass of an object is 44 kilograms and its velocity is 10 meters per second east, how much Kinetic Energy does it have?
olya-2409 [2.1K]
Given: Mass m = 44 Kg;      Velocity v = 10 m/s

Required: Kinetic energy K.E = ?

Formula: K.E = 1/2 mv²

               K.E 1/2 (44 Kg)(10 m/s)²

               K.E = 2,200 Kg.m²/s²

               K.E = 2,200 J Answer is A
8 0
3 years ago
A ball starts at rest and rolls down an inclined plane. The ball reaches 7.5 m/s in 3 seconds. What is the acceleration?
just olya [345]

Answer:

a=2.5\ m/s^2

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly over time.

The equation that describes the change of velocities is:

v_f=v_o+at

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

Solving the equation for a:

\displaystyle a=\frac{v_f-v_o}{t}

The ball starts at rest (vo=0) and rolls down an inclined plane that makes it reach a speed of vf=7.5 m/s in t=3 seconds.

The acceleration is:

\displaystyle a=\frac{7.5-0}{3}

\boxed{a=2.5\ m/s^2}

7 0
2 years ago
Which letter represents the location of the resister in this diagram? A B C D​
Elodia [21]

Answer:

A

Explanation:

7 0
2 years ago
Read 2 more answers
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