All categories

3 years ago

What is meant by cathode rays?what is radio activity and state three of it's effects?

Physics

1 answer:

stealth61 [152]3 years ago

5 0

1cathode rays plural : the high-speed electrons emitted in a stream from the heated cathode of a vacuum tube

2: a stream of electrons emitted from the cathode of a vacuum tube —usually used in plural

You might be interested in

What is the photosphere?

Arte-miy333 [17]

The photosphere<span> is the visible "surface" of the Sun (left</span>

6 0

3 years ago

Read 2 more answers

A baseball is hit from a height of 4 feet above the ground with an initial velocity of 110 feet per second and at an angle of 35

mrs_skeptik [129]

Answer:

Part a)

$h = 62.2 ft$

Part b)

It will not able to cross the pole

Explanation:

As we know that ball is hit with speed of 110 ft/s at an angle of 35 degree

so here we will say

$v_y = 110 sin35$

$v_x = 110 cos35$

now at the maximum height the vertical velocity will become zero

so here we can use kinematics

$v_f^2 - v_y^2 = 2 a h$

here we have

$a = -32 ft/s^2$

$v_f = 0$

$v_y = 63.1 ft/s$

now we have

$0 - 63.1^2 = 2(-32)h$

$h = 62.2 ft$

Part b)

now the height of ball is related to the distance from point of projection is given as

$y = xtan\theta - \frac{gx^2}{2v^2cos^2\theta}$

now we know that

$x = 375 ft$

$y = 375(tan35) - \frac{(32)(375^2)}{2(110^2)(cos35)^2}$

$y = 262.6 - 277.12 = -14.5 ft$

since its coming negative so it will not able to cross the pole

3 0

3 years ago

What is social play?

Ugo [173]

social play happens when children are playing with adults or with other kids

6 0

3 years ago

a 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

Lesechka [4]

The final velocity is 3.47 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the two players before and after the collision must be conserved:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 91.5 kg$ is the mass of the first player

$u_1 = 3.73 m/s$ is the initial velocity of the first player (we take east as positive direction)

$m_2 = 63.5 kg$ is the mass of the second player

$u_2 = 3.09 m/s$ is the initial velocity of the second player

$v$ is their final combined velocity after the collision

Re-arranging the equation and substituting the values, we find:

$v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(3.73)+(63.5)(3.09)}{91.5+63.5}=3.47 m/s$

So, their velocity afterwards is 3.47 m/s east.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

6 0

3 years ago

A football coach walks 10 meters eastward and then 18 meters westward and then 22 metered East ward and finally 34 meters westwa

34kurt

Well you never specified what you're asking... however, this might help you learn the concepts of displacements and magnitude.

: The official displacement formula is as follows: s = sf - si. s = displacement; si = initial position; sf = final position

magnitude is the quantitative value of seismic energy. It is a specific value having no relation with distance and direction of the epicentre.

the magnitude of a vector in any dimension. For a 2d vector the formula is [math]|z| = \sqrt{x^2+y^2}[/math], where x and y are the x and y components of the vector respectively.

7 0

3 years ago

Read 2 more answers

What is meant by cathode rays?what is radio activity and state three of it's effects?​

What is meant by cathode rays?what is radio activity and state three of it's effects?