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3 years ago

Explain how the velocity of the aeroplane will change in the vertical direction

Physics

1 answer:

Anuta_ua [19.1K]3 years ago

7 0

Answer:

The vertical velocity of a projectile changes by 9.8 m/s each second, The horizontal motion of a projectile is independent of its vertical motion.

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All are examples of electric forces except _________. A. a neutron pushing on another neutron B. an electron pushing on a proton

Contact [7]

Answer:

A) a neutron pushing on another neutron.

Explanation:

Neutrons have no charge, therefore, there is no electric force among them. Protons and electrons on the other hand do have electric charge (electrons negative charge and protons positive charge) that generate electric forces between them that can be repelling forces (if the charges are of the same sign), or attractive forces (if the charges are of opposite signs).

6 0

4 years ago

a train engineer drives a train 235 km north along a straight track . then he drives the train back south 126 km . finally , he

yuradex [85]

let here North direction is along +Y and South direction is along -Y

similarly East direction is towards +X and west direction is towards -X

now it is given that

first it moves 235 km north

$d_1 = 235 \hat j$

then it moves back 126 km south

$d_2 = - 126 \hat j$

then again he moves north

$d_3 = 45 \hat j$

now the total displacement is given as

$d = d_1 + d_2 + d_3$

$d = 235 - 126 + 45 = 154 km$

so final displacement of train is 154 km North

5 0

4 years ago

An object is placed a distance of 20 cm from a convex mirror of radius 40 cm. How far (in cm) is the image from the mirror?

Leona [35]

Answer:

Be sure you understand two optics principles: the focal length of a convex mirror is NEGATIVE (by convention) and R / 2 = f.

Find f, take its negative, plug in the mirror equation and obtain Di = - 24 cm. This indicates that the image is virtual (as it should be in a convex mirror), is erect (as all virtual images are), is diminished (as it should be) and INSIDE the mirror as it should be.

Explanation:

3 0

4 years ago

A barge of mass 5.00 ×104 kg is pulled along the Erie Canal by two mules, walking along towpaths parallel to the canal on either

boyakko [2]

Answer: 219,344.5 j

Explanation:

from the question we have the following parameters

mass of barge (m) = 5 x 10^4 kg

angle of ropes (θ) = 45 degrees

force by each mule (F1) = 1.10 kN = 1100 N

force by each mule (F2) = 1.10 kN = 1100 N

distance (s) = 141 m

work done by the mules = force x cos θ x distance

since we are calculating the force of both mules we have to both mules before we can use in the equation

force = 1100 + 1100 = 2200 N

work done = 2200 x cos (45) x 141

work done = 219,344.5 j

5 0

3 years ago

an aluminium bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. the hole is 30mm in diameter and i

zavuch27 [327]

Answer:

ΔL = 1.011 mm

Explanation:

Let's begin by listing out the given information:

Length (L) = 600 mm = 0.6 m,

Diameter (D) = 40 mm = 0.04 m ⇒ Radius (r) = 20 mm = 0.2 m,

Area (cross sectional) = πr² = 3.14 x .02² = 0.001256 m²,

Modulus of Elasticity (E) = 85 GN/m²,

Compressive load (F) = 180 KN

Using the formula, Stress = Load ÷ Area

Mathematically,

σ = F ÷ A = 180 x 10³ ÷ 0.001256

σ = <u>143312.1 KN/m</u>²

Modulus of elasticity = stress ÷ strain

E = σ ÷ ε

ε = ΔL/L

85 x 10⁹ = 143312.1 x 10³ ÷ (ΔL/L)

ΔL = 143312.1 x 10³ ÷ 85 X 10⁹ = 1686.02 * 10⁻⁶

ΔL = L x 1686.02 * 10⁻⁶

ΔL = 0.6 * 1686.02 * 10⁻⁶ = 1011.61 x 10⁻⁶

ΔL = 1.011 x 10⁻³ m

ΔL = <u>1.011 mm</u>

∴The bar contracts by 1.011 mm

4 0

3 years ago