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Bingel [31]
1 year ago
11

What is the effect on a field of tall grass when a wave caused by a cool summer breeze passes through the field?

Physics
1 answer:
mihalych1998 [28]1 year ago
7 0

Whenever a wave is brought on by a cool summer breeze across the field. The grass tilts in the wind's direction before reverting to its original posture. Option A is correct.

<h3>What is the wind blowing?</h3>

Air pressure variations within our atmosphere result in the wind, which is the movement of air.

Areas with a low pressure are approached by air in high pressure. The air flows more quickly when there is a bigger pressure differential. Most rapid winds.

The wind is moving air and is caused by differences in air pressure within our atmosphere.

Air under high pressure moves toward areas of low pressure. The greater the difference in pressure, the faster the air flows. The Fastest Winds.

Hence, option A is correct.

To learn more about the wind blowing refer;

brainly.com/question/14212137

#SPJ1

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if a ball is rolling at a velocity of 1.5 m/sec and has the momentum of 10.0 kg m/sec, what is the mass of the ball?
PolarNik [594]
Okay. There is a simple formula to go with this where:

p = mv

P: Momentum.
M: Mass.
V: Velocity

Sub the numbers in and solve for M.

10.0 = m(1.5)
10.0/1.5 = m
6.67 kg = m

Therefore the mass of the ball is 6.67kg.
6 0
3 years ago
Determine the length of the tungsten filament in a 100 watt lightbulb given: (i) the resistivity of tungsten is 5.6 × 10−8 Ω · m
svetoff [14.1K]

Answer:

0.34148 m

Explanation:

\rho = Resistivity of tungsten = 5.6\times 10^{-8}\ \Omega m

d = Diameter = 0.0018 inch

r = Radius = \dfrac{r}{2}=\dfrac{0.0018}{2}=0.0009\ in

r=0.0009\times 0.0254=0.00002286\ m

\alpha = Temperature coefficient of tungsten = 0.0045 /^{\circ}C

Power is given by

P=\dfrac{V^2}{R}\\\Rightarrow R=\dfrac{V^2}{P}\\\Rightarrow R=\dfrac{120^2}{100}\\\Rightarrow R=144\ \Omega

We have the equation

R_2=R_1[1+\alpha(T_2-T_1)]\\\Rightarrow R_1=\dfrac{R_2}{1+\alpha(T_2-T_1)}\\\Rightarrow R_1=\dfrac{144}{1+0.0045(2550-25)}\\\Rightarrow R_1=11.64812\ \Omega

Resistance is given by

R=\rho\dfrac{l}{A}\\\Rightarrow l=\dfrac{RA}{\rho}\\\Rightarrow l=\dfrac{11.64812\times \pi (0.00002286)^2}{5.6\times 10^{-8}}\\\Rightarrow l=0.34148\ m

The length of the filament is 0.34148 m

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3 years ago
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