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Ugo [173]
3 years ago
15

Jean is making bar graphs for a representation. She is planning for the length and width of the bars to have a ratio of 3:2, so

that they satisfy this equation.
2l = 3w

If one of the bars is 7 centimeters wide, what should be it's length. Find and explain how you found the solution to this answer.

A.21 cm

B. 14 cm

C. 10 1/2 cm

D. 4 2/3 cm

Please explain how you found the answer.
Mathematics
1 answer:
raketka [301]3 years ago
6 0

Answer: C. 10\frac{1}{2}\ cm


Step-by-step explanation:

Given: The ratio of length to width = 3:2,such that the equation she formed is

2l=3w

The width of bar w= 7 cm

Then substitute this value in the equation and solve , we get

2l=3\times7\\\Rightarrow2l=21\\\Rightarrow\ l=\frac{21}{2}\\\Rightarrow\ l=10\frac{1}{2}

Hence the length of the bar = 10\frac{1}{2}\ cm

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3 years ago
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Step-by-step explanation:

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3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

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The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

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C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

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7 0
3 years ago
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The answer to number 23 is D, 49.
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irinina [24]

Answer:

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15/5=3

so 3x3= 9 miles

3 0
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