All categories

4 years ago

A case of Mountain Dew (24 cans) cost $7.68. What is the unit price?

Mathematics

2 answers:

Sergio [31]4 years ago

8 0

Answer:

The answer is $0.32.

Step-by-step explanation:

You achieve this answer by taking the total price ($7.68) divided by the number of units for that price (24 cans). Therefore:

$\frac{7.68}{24} = 0.32$

Westkost [7]4 years ago

3 0

0.32 cents for each unit because if you divide 7.68 by 24 it is 0.32

You might be interested in

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

2 years ago

I really need help with this chart !! 20 points !!

vichka [17]

Lean is 5 and the quasretiv

5 0

4 years ago

A rectangular garden has a walkway around it. The area of the garden is 6(5.5x + 2.5). The

Lorico [155]

Answer:The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

A rectangular garden has a walkway around it

1. The area of the garden is 4(4.5 x + 1.5)

2. The combined area of the garden and the walkway is 5.5(8 x + 4)

We need to find the area of the the walkway

To find the area of the walkway by subtracting the area of the

rectangle from the combined area

∵ The combined area = 5.5(8 x + 4) ⇒ simplify it

∴ The combined area = 5.5(8 x) + 5.5(4)

∴ The combined area = 44 x + 22

∵ The area of the garden = 4(4.5 x + 1.5) ⇒ simplify it

∴ The area of the garden = 4(4.5 x) + 4(1.5)

∴ The area of the garden = 18 x + 6

Now subtract the area of the garden from the combined area

∵ Area of the walkway = (44 x + 22) - (18 x + 6)

∴ Area of the walkway = 44x + 22 - 18 x - 6

- Add like terms

∴ Area of the walkway = (44 x - 18 x) + (22 - 6)

∴ Area of the walkway = 26 x + 16

The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

5 0

3 years ago

Sin(x) + sin(3x) = 4 sin(x) cos^2(x)<br> Prove the identity.

salantis [7]

$\bf \textit{Sum to Product Identities} \\\\ sin(\alpha)+sin(\beta)=2sin\left(\cfrac{\alpha+\beta}{2}\right)cos\left(\cfrac{\alpha-\beta}{2}\right)\leftarrow \textit{we'll use this one} \\\\\\ sin(\alpha)-sin(\beta)=2cos\left(\cfrac{\alpha+\beta}{2}\right)sin\left(\cfrac{\alpha-\beta}{2}\right) \\\\\\ \stackrel{\textit{symmetry identity}}{cos(-\theta )=cos(\theta )} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf sin(x)+sin(3x)=\underline{4sin(x)cos^2(x)} \\\\[-0.35em] ~\dotfill\\\\ sin(x)+sin(3x)\implies 2sin\left( \cfrac{x+3x}{2} \right)cos\left( \cfrac{x-3x}{2} \right) \\\\\\ 2sin\left( \cfrac{4x}{2} \right)cos\left( \cfrac{-2x}{2} \right)\implies 2sin(2x)cos(-x)\implies 2\boxed{sin(2x)} cos(x) \\\\\\ 2\boxed{2sin(x)cos(x)} cos(x)\implies \underline{4sin(x)cos^2(x)}$

6 0

4 years ago

A magnitude 6.7 earthquake struck the SanFernando valley region of Los Angeles in 1994, causing widespread damage. Suppose anoth

madam [21]

Answer: 2.308 .

Step-by-step explanation:

Let X denotes the number of earthquakes in SanFernando valley region of Los Angeles in 1994.

Given: $\mu=17.6$

Probability is 0.87 that there will be at least 15 earthquakes .

i.e. $P(X\geq15)=0.87$

$\Rightarrow\ P(\dfrac{X-\mu}{\sigma}\geq\dfrac{15-17.6}{\sigma})=0.87\\\\ \Rightarrow\ P(Z\geq\dfrac{-2.6}{\sigma})=0.87\ \ \ [Z=\dfrac{X-\mu}{\sigma}]$

Z-value corresponding to p-value 0.87 is -1.1263 .

So, $\dfrac{-2.6}{\sigma}=-1.1263$

$\sigma= \dfrac{-2.6}{-1.1263}\approx2.308$

Hence, the required standard deviation = 2.308 .

4 0

3 years ago