Answer:
0.034 = 34×10^-3
Explanation:
This is because the special point is notated until it goes in front of the first counting number
<span>Dmitri Mendeleev thats the answer</span>
Answer:
In the third step of the citric acid cycle, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released.
Explanation:
In the first step of citric acid cycle, acetylCoA combines with a four-carbon molecule, oxaloacetate, forming a six-carbon molecule, citrate.
In the second step, the citrate in the presence of enzyme anicotase is converted into isocitrate.
<u>In the third step, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released leaving behind one five-carbon molecule called as α-ketoglutarate. During this step, NAD⁺ is reduced to form NADH. </u>
<u>This is first round of the citric acid cycle that could possibly release a carbon atom originating from this acetyl CoA.</u>
On series of reaction, another carbon dioxide molecule also being relased and oxaloacetate is regenerated again.
Answer:
70.15 cm³
Solution:
Data Given;
Mass = 55 g
Density = 0.784 g.cm⁻³
Required:
Volume = ?
Formula Used:
Density = Mass ÷ Volume
Solving for Volume,
Volume = Mass ÷ Density
Putting values,
Volume = 55 g ÷ 0.784 g.cm⁻³
Volume = 70.15 cm³
