Answer:
Answer to the question:
Explanation:
Differences between ionic bond and covalent bond:
The ionic bond occurs between two different atoms (metallic and non-metallic), while the covalent bond occurs between two equal atoms (non-metallic).
In the covalent bond there is an electron compartment, while in the ionic bond there is an electron transfer.
Ionic bonds have a high melting and boiling point, while covalent bonds usually have a low point.
Explanation:
identified by one of the Chi Omega survivors as the assailant, and hair and fiber evidence tied him to the Leach murder. His trial for the Florida attacks in June 1979 was the first-ever nationally televised trial in the United States.
I guess the problem is asking for the distance between Earth and Mars in Astronomical Units (AU).
Since

and the distance between the two planets is

we can convert this distance into AU by using the following proportion:

from which we find
Answer:
<h3>2139 Million years</h3>
Explanation:
Half life of a material is the time required for the material to decay into half of initial amount.
initially there is 26 grams of uranium-235, and the final amount is 3.25 gram
ratio between initial and final amount = 
now it is clear that the material have halved 3 times from initial condition
number of half lives passed = 3
number of half lives passed can also be found using the equation
no of half lives = 
where
is the initial amount of material and R is the final amount
∵ Number of half lives = 
= 3
So, age of rock = half-life X number of half-lives passed
=713000000 X 3
= 2139000000
=2139 Million Years
<span>Integrate a to get v and use initial data for v to evaluate the constants of integration.
v = [(3/2)t^2 + Ci]i + [2t^2 + Cj]j
When t=0, v = 5i + 2j, hence Ci=5, Cj=2
So v = [(3/2)t^2 + 5]i + [2t^2 + 2]j <==ANS
(b)
Integrate v to get r and use initial data for r to evaluate the constants of integration:
The result is:
r = [0.5t^3 + 5t + 20]i + [(2/3)t^3 + 2t + 40]j <==ANS
Set t=4 in the above expression to evaluate (c)
Convert the result of (c) to polar form to evaluate (d)</span>