Two parallel plates of area 0.155 m2 are separated by 0.00100 m. What is their capacitance?
1 answer:
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Answer:
The maximum energy that can be stored in the capacitor is 6.62 x 10⁻⁵ J
Explanation:
Given that,
dielectric constant k = 5.5
the area of each plate, A = 0.034 m²
separating distance, d = 2.0 mm = 2 x 10⁻³ m
magnitude of the electric field = 200 kN/C
Capacitance of the capacitor is calculated as follows;
Maximum potential difference:
V = E x d
V = 200000 x 2 x 10⁻³ = 400 V
Maximum energy that can be stored in the capacitor:
E = ¹/₂CV²
E = ¹/₂ x 8.275 x 10⁻¹⁰ x (400)²
E = 6.62 x 10⁻⁵ J
Therefore, the maximum energy that can be stored in the capacitor is 6.62 x 10⁻⁵ J
Explanation:
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Answer: 31.33 degrees
Explanation:
The diffraction angles when we have a slit divided into
parts are obtained by the following equation:
(1)
Where:
is the width of the slit
is the wavelength of the light
is an integer different from zero.
Now, the first-order diffraction angle is given when , hence equation (1) becomes:
(2)
Now we have to find the value of :
(3)
We know:
In addition we are told the diffraction grating has 5000 slits per mm, this means:
Substituting the known values in (3):
<u>Finally:</u>
>>>This is the first-order diffraction angle