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Jet001 [13]
3 years ago
7

After a projectile is fired into the air, what is the acceleration in the x-direction? (Assume no air resistance.)

Physics
2 answers:
storchak [24]3 years ago
5 0

Answer:

a_x = 0

Explanation:

When projectile is in air then the force on the projectile is only due to its weight

It is vertically downwards

F_g = mg(-\hat j)

so here since we don't have any air drag or friction due to air so there will be no force along its tangent or along x direction

so the acceleration along x direction will be zero

a_x = 0

a_y = - g

Gre4nikov [31]3 years ago
4 0
Without air resistance, there is no horizontal force on the projectile,
so it has no horizontal acceleration.  The answer is "zero".
 
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Sveta_85 [38]

Answer:

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M= Mass (kg)

G= Gravitational field strength (N/kg)

H= Hight (m)

PE= Gravitational Potential Energy (J)

Explanation:

Gravitational Potential Energy is the energy stored in a object due to its position above the Earth's surface.

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3 years ago
A 1.0-μm-diameter oil droplet (density 900 kg/m3) is negatively charged with the addition of 39 extra electrons. It is released
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Answer:

6.75\mu C/m^2

Explanation:

We are given that

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Total charge=q=ne=39\times 1.6\times 10^{-19}=62.4\times 10^{-19} C

Distance,s=2mm=2\times 10^{-3} m

Mass =density\times volume=900\times \frac{4}{3}\pi r^3=900\times \frac{4}{3}\pi(0.5\times 10^{-6})^3=4.7\times 10^{-16} kg

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qE=ma

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\sigma=\frac{2\epsilon_0ma}{q}=\frac{2\times 8.85\times 10^{-12}\times 4.7\times 10^{-16}\times 5062.5}{62.4\times 10^{-19}}

\epsilon_0=8.85\times 10^{-12}

\sigma=6.75\times 10^{-6}C/m^2=6.75\mu C/m^2

6 0
3 years ago
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Based on Newton's principle, whenever objects A and B interact with each other, they exert forces upon each other.

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