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krok68 [10]
3 years ago
12

Which of the following atoms will not react with water​

Chemistry
1 answer:
Sati [7]3 years ago
3 0

Answer:

Among Na ,K , Pb , Li , The atom which does not react with water is :

<u>Pb</u>

Explanation:

Li  : Reacts slowly with water

Na ,K  : Reacts vigorously with water

Pb : It does not reacts with water because :- Pb oxidize in presence of  atmospheric oxygen to form lead oxide (PbO) . this PbO form a layer over the surface of Pb and make it inert to water.

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What is the wavelength of a 3 x 1012 Hz infrared wave?
Alenkasestr [34]

Answer:

D

Explanation:

wavelength = speed of light/ frequency

= (3 x 10^8 m/s) / (3 x 10^12 Hz)

= 1 x 10^-4 m

5 0
2 years ago
Please help
Mashutka [201]

Answer:

Potential

Explanation:

The answer is potential!

6 0
2 years ago
Read 2 more answers
A 10.0 mL sample of HNO3 was exactly neutralized by 13.5 mL of 1.0 M KOH. What is the molarity of the HNO3? Use the titrations f
Kruka [31]

Answer: Thus molarity of HNO_3 is 1.35 M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=1.0M\\V_2=13.5mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 1.0\times 13.5\\\\M_1=1.35M

Thus molarity of HNO_3 is 1.35 M

7 0
3 years ago
Which has a larger radius Me or Xe?
IrinaVladis [17]
Xe is bigger:)

I hope I helped:)

Please leave a thanks:)
8 0
3 years ago
Calculate the percent covalent character of a chemical bond between oxygen and beryllium.
dezoksy [38]

Beryllium Oxide has a molecular formula Be-O

% covalent character in Be-O = 100 - % ionic character in Be-O

Now,

% ionic character = {1 - exp[(-0.25)(E(Be)-E(O))²]}*100

where,

E(Be) and E(O) are the electronegativity values of Be and O

Based on the Paulings scale:-

E(Be) = 1.57

E(O) = 3.44

% ionic = {1 - exp[(-0.25)(1.57-3.44)²]}*100 = 58.28%

Therefore, % covalent = 100 -58.28 = 41.72%

Ans: b) 41 percent

8 0
3 years ago
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