A radio-controlled car increases its kinetic energy from 3 J to 10 J over a distance of 1 m. What was the average net force on t
1 answer:
Answer:
Net force, F = 7 N
Explanation:
It is given that,
Initial kinetic energy of the car,
Final kinetic energy of the car,
Distance, d = 1 m
We need to find the average net force on the car during this interval. It is given by using the work energy theorem as :
Also, W = F.d d = distance and F = net force
F = 7 Newton
So, the average net force on the car during this interval is 7 newton. Hence, this is the required solution.
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Answer:
1. The stone will strike the ground 49.46 m from the base of the cliff
2. A) Approximately 0.542 seconds
B) Approximately 3.69 m/s
3. A) The time the ball spends in the air is approximately 4.0775 s
B) The horizontal range is approximately 141.25 m.
Explanation:
1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)
∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds
The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m
The stone will strike the ground 49.46 m from the base of the cliff
2. A) The time the ball spends in the air = t = √(h/(1/2 × g)
∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds
B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s
The initial horizontal velocity ≈ 3.69 m/s
3. A) The time the ball spends in the air is given by the following equation;
t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s
t ≈ 4.0775 s
B) The horizontal range, R, of the ball is given by the equation for the range of a projectile as follows;
Substituting the known values, gives;
The horizontal range ≈ 141.25 m.