To make things simple you can first find out what 8 1/16 is. 8 1/16 is approximately 8.0625. Then find what 5 1/2 is which is 5.5. Now all you have to do is subtract 5.5 from 8.0625 (8.0625-5.5) and that should be equal to 2.5625.
If a radioactive substance remains 80% of the initial amount then the half life of the radioactive substance is 2.5 years.
Given 80% of the initial amount of a radioactive substance remains.
If after 1 year the value or weight of the radioactive substance remains 80% means the rate of disappearing is 20% per annum.
If we clearly observe then it is forming a geometric progression and the rate is 80%.
Geometric progression will be if we assume the initial quantity be 100
is:
100,80,64,.........
we have to calculate the value of years in the value of term is 0.
the value of nth term of a geometric progression is
so,
r is 0.8
100*=0
=0
if we calculate this we will find n-1=11
n=12
So the full life of radioactive substance is 12 and the half life will be 6 years.
Learn more about geometric progression here brainly.com/question/12006112
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so you want to get x to one side only.
3.4x-5=2.4x
add 5 to both sides
3.4x=2.4x+5
now get x to one side by subtracting 2.4x
so x=5
It is 17.86 percent I just rounded it but it was originally 17.8571429%
To find out the answer of the two multiplied products with the help of partial products we separate into unit based numbers so as to, for easier calculation and simplification with units of zeroes. So, in this case we are given the product of 4 times of 652.
Here we need to expand this product of higher number to zeroes and take aside the added numbers to come back to the original multiple of a product. That is:
We just separated and expanded the product to be multiplied by removing other units following it. Same goes for other units at Hundredth, tenth and unitary position.
Therefore,
For tenth term.
The terms after splitting and expanding the product before multiplication is:
Multiply the product elements in individual manner and add the elements forged by individual multiplication to get the required solution.
Hope it helps.