All categories

3 years ago

What is the rate of acceleration of a 2,000 kilogram truck if a force of 4,200 N is used to make it start moving forward?

Physics

2 answers:

gizmo_the_mogwai [7]3 years ago

7 0

Answer: 2.1

Explain:
F = ma
a = F/m = 4,200/ 2,000
a = 2.1

Svetlanka [38]3 years ago

3 0

2.1m/s^2 is the answer to
Your question. I hope that helps.

You might be interested in

Two copper rods are separated by a small gap at B. Rod AB has a diameter of 200mm and rod BC has a diameter of 150mm. Find the f

gulaghasi [49]

Answer:

A)3.8196 * $10^{9}$ Newtons B) 2.153 * $10^{9}$ Newtons

Explanation:

Force = Pressure * Area.

Pressure is given as 120GPa

Area = Cross Sectional Area of Rod = Area Of A circle = π $R^{2}$ .

Area Expansivity β = $\frac{Change in Area}{Original Area * Temperature Rise}$

Area Expansivity β = 2α

α = 16.9x10-6/ ° C.

Radius of Rod AB = Half 0f Diameter, 200mm = $\frac{0.2m}{2}$ = 0.1 m

Radius of Rod BC = Half Of Diameter, 150mm = $\frac{0.15}{2}$ = 0.075 m.

Note: To convert from millimeter to meter you divide by 1000.

Area of Rod AB = π * $0.1^{2}$ = 0.0314 $m^{2}$

Area of Rod BC = π * $0.075^{2}$ = 0.0177 $m^{2}$ .

Change in Area = 2α * Original Area * Temperature Rise. Therefore for

Rod AB = 2 * 16.9* $10^{-6}$ * 0.0314 * 30 = 3.183 * $10^{-5}$ $m^{2}$ .

For Rod BC we have = 2 * 16.9* $10^{-6}$ * 0.0177 * 30 = 1.794∈-5 $m^{2}$ .

The forces on each rods will be given by.

Force AB = Pressure * Area of Rod AB

= 120GPa * 3.183 * $10^{-5}$ gives 3.8196 * $10^{9}$ Newtons.

Force BC = Pressure * Area of Rod BC

= 120GPa * 1.794 * $10^{-5}$ gives 2.153 * $10^{9}$ Newtons

7 0

3 years ago

Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground

Setler79 [48]

They will both hit the ground at the same time because gravitational acceleration for all objects is the same.

6 0

3 years ago

When you solve an equation the ___________ of ___________ must be treated like any other mathematical quantity— they must be mul

Aneli [31]

when you solve an equation the quadratic of g(f) must be treated like any other mathematical quantity— they must be multiplied, divided, raised to powers, cancelled, etc in exactly the same way as the numbers to which they belong

5 0

3 years ago

What can i do to recycle?

mafiozo [28]

Answer:

You could throw away the following items:

Mixed paper: Newspaper, magazine, junk mail, cardboard, frozen food packaging, wrapping paper, paper bags, etc.

Cans: aluminum, foil, tin, steal, aerosol (empty without pressure) and metal food trays. ...

Unbroken glass: Wine bottles, bottles and jars.

Plastic: Rigid containers like milk jugs, shampoo or water bottles.

Hope this helped

8 0

3 years ago

A 4 kg mass is in free fall. What is the velocity of the mass after 11 seconds

Ksju [112]

Velocity of the mass after 11 seconds = ( value of the gravitational acceleration) * ( time )
velocity = ( 9.81 m / s^2 ) ( 11)
velocity = 107.91 meters per second

5 0

3 years ago