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goldfiish [28.3K]
2 years ago
14

What is the rate of acceleration of a 2,000 kilogram truck if a force of 4,200 N is used to make it start moving forward?

Physics
2 answers:
gizmo_the_mogwai [7]2 years ago
7 0
Answer: 2.1

Explain:
F = ma
a = F/m = 4,200/ 2,000
a = 2.1
Svetlanka [38]2 years ago
3 0
2.1m/s^2 is the answer to
Your question. I hope that helps.
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A string of length L, fixed at both ends, is capable of vibrating at 309 Hz in its first harmonic. However, when a finger is pla
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Answer:

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Explanation:

A fixed string at both ends presents a phenomenon of standing waves, two waves with the same frequency that are added together. The expression to describe these waves is

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The first harmonic or leather for n = 1

Wave speed is related to wavelength and frequency

     v = λ f

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Let's replace in the first equation

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For the shortest length L = L-l

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These two equations form our equation system, let's eliminate v

    v = 2L f₁

    v = 2 (L-l) f₂

    2L f₁ = 2 (L-l) f₂

    L- l = L f₁ / f₂

    l = L - L f₁ / f₂

    l = L (1- f₁ / f₂)

.

Let's calculate

    l / L = (1- 309/463)

    i / L = 0.3326

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