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goldfiish [28.3K]
3 years ago
14

What is the rate of acceleration of a 2,000 kilogram truck if a force of 4,200 N is used to make it start moving forward?

Physics
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0
Answer: 2.1

Explain:
F = ma
a = F/m = 4,200/ 2,000
a = 2.1
Svetlanka [38]3 years ago
3 0
2.1m/s^2 is the answer to
Your question. I hope that helps.
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A distance of d is covered with 53 mile/hr initially. Time taken to cover this distance t1 = d/53 hour Next distance of d is covered with x mile hours. Time taken to cover this distance t2 = d/x hours. We have average speed = 26.5 mile / hour          

                                         = Total distance traveled/ total time taken                  

                                         = \frac{2d}{\frac{d}{53}+\frac{d}{x}} = \frac{2}{\frac{1}{53}+\frac{1}{x} }  = \frac{106x}{x+53}

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A.reduce by 4.

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