Hello, I see you are in a jam. Lemme help.
1.) True
2.) True
3.) True
4.) True
5.) True
LOL these are all true ;)
Answer:
The magnitude of the magnetic force this particle experiences is 
.
Explanation:
Given that,
Velocity v= (3i-5j+k) m/s
Magnetic field B=(i+2j-k) T
We need to calculate the value 
We need to calculate the magnitude of the magnetic force this particle experiences
Using formula of magnetic force
Put the value into the formula
Hence, The magnitude of the magnetic force this particle experiences is .
Answer:
Δx = 3.99 m
Explanation:
To determine distance, use kinetic energy
will make it short and easy.
KE=1/2mv2 and KE=Δxmgμ
Set the equations equal to each other
1/2mv2=Δxmgμ (Note: The masses cancel
)
1/2v2=Δxgμ Solve for Δx
where g=9.8
Δx=v2/(2gμ) Δx = 25 / (2 * 9.8 * 0.32) Δx = 3.99 m
Please let me know if its correct, if not report it so we can correct it.
The time interval in which the larger force act is 1.1 seconds.
<h3>What is impulse?</h3>
The impulse produced by an object is determined from the product of force and time of force of the object.
The impulse experienced by an object is the product of mass and velocity of the object or simply the impulse experienced by object is equal to change in the momentum of an object.
J = Ft
where;
- F is the applied force
- t is the time of force acting
The magnitude of the force that produce impulse of 3 Ns for 3.2 seconds is calculated as;
F = J/t
F = (3 Ns) / (3.2 s)
F = 0.94 N
The magnitude of the force that is three times larger is calculated as;
F₂ = 3 x 0.94 N
F₂ = 2.82 N
The time interval of the larger force is calculated as;
t₂ = J/F₂
t₂ = 3 / 2.82
t₂ = 1.1 seconds
Thus, the impulse experienced by an object is a function of force and time of force action.
Learn more about impulse here: brainly.com/question/25700778
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