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e-lub [12.9K]
3 years ago
11

Wireless Internet networks, including many used in homes, often make use of high-frequency radio waves. High-frequency waves are

useful because they can carry a lot of information. However, high-frequency waves are less capable of passing through objects than are low-frequency waves. As a result, waves traveling from a person's wireless laptop computer, for example, could be interrupted by objects between the computer and the modem.
Due to this limitation of high frequency waves, which of the following statements best explains why digital waves are commonly used in high-frequency wireless networks instead of analog waves?
A.
Analog waves cannot reach high enough amplitudes to be used in wireless networks.
B.
Analog waves cannot reach large enough wavelengths to be used in wireless networks.
C.
It is easier to correct small disruptions in digital waves than in analog waves.
D.
Small disruptions in analog waves are more easily corrected than in digital waves.
Physics
2 answers:
IgorLugansk [536]3 years ago
7 0

Answer:

The CORRECT answer is c

lutik1710 [3]3 years ago
4 0
The answer is d , small disruptions
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Answer:

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       \theta_{1} = \frac{\omega_{f1}^{2}}{2*\alpha } = \frac{(4.9rad/sec)^{2}}{2*2.38*e-3rad/sec2} = 5044.12 rad (3)

  • The second displacement θ₂, (since along it the propeller rotates at a constant angular speed equal to (1), can be found just applying the definition of average angular velocity, as follows:

       \theta_{2} =\omega_{f1} * \Delta_{t2} = 4.9 rad/s * 1.48*e3 s = 7252 rad (4)

  • Finally we can find the third displacement θ₃, applying the same kinematic equation as in (2), taking into account that the angular initial speed is not zero anymore:

       \omega_{f2}^{2} - \omega_{o2}^{2} = 2* \alpha *\Delta\theta (5)

  • Replacing by the givens (α, ωf₂) and ω₀₂ from (1) we can solve for Δθ as follows:

      \theta_{3} = \frac{(\omega_{f2})^{2}- (\omega_{f1}) ^{2} }{2*\alpha } = \frac{(2.42rad/s^{2}) -(4.9rad/sec)^{2}}{2*(-2.63*e-3rad/sec2)} = 3451.25 rad (6)

  • The total angular displacement is just the sum of (3), (4) and (6):
  • Δθ = θ₁ + θ₂ + θ₃ = 5044.12 rad + 7252 rad + 3451.25 rad
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